Subtraction of Unlike Fractions

We will learn how to solve subtraction of unlike fractions. In order to subtract unlike fractions first we convert them as like fractions.

To subtract unlike fractions, we first convert them into like fractions. In order to make a common denominator, we find LCM of all the different denominators of given fractions and then make them equivalent fractions with a common denominators.

Let us consider some of the examples of subtracting unlike fractions:

1. Subtract 1/10 from 2/5.

Solution:

2/5 - 1/10

The L.C.M. of the denominators 10 and 5 is 10.

2/5 = (2 × 2)/(5 × 2) = 4/10, (because 10 ÷ 5 = 2)

1/10 = (1 × 1)/(10 × 1) = 1/10, (because 10 ÷ 10 = 1)

Thus, 2/5 - 1/10

= 4/10 - 1/10

= (4 - 1)/10

= 3/10


2. Subtract \(\frac{3}{8}\) from \(\frac{5}{12}\).

Solution:

Let us find the LCM of denominators 8 and 12. LCM is 24.

\(\frac{3}{8}\) = \(\frac{3 × 3}{8 × 3}\) = \(\frac{9}{24}\) and

\(\frac{5}{12}\) = \(\frac{5 × 2}{12 × 2}\) = \(\frac{10}{24}\)

Now, subtract \(\frac{9}{24}\) and \(\frac{10}{24}\).

\(\frac{10}{24}\) - \(\frac{9}{24}\)                                    

= \(\frac{10 - 9}{24}\)

= \(\frac{1}{24}\)

Let us illustrate the above example pictorially as shown below.

Subtraction of Fractions

The whole strip above has 24 equal parts. The fraction \(\frac{5}{12}\) is equal to \(\frac{10}{24}\). So the shaded portion represents \(\frac{10}{24}\). We take away \(\frac{3}{8}\) or \(\frac{9}{24}\) of the above strip. The remaining part represents \(\frac{1}{24}\) of the whole strip.


3. Subtract 4/9 from 5/7.

Solution:

5/7 - 4/9

The L.C.M. of the denominators 9 and 7 is 63.

5/7 = (5 × 9)/(7 × 9) = 45/63, (because 63 ÷ 7 = 9)

4/9 = (4 × 7)/(9 × 7) = 28/63, (because 63 ÷ 9 = 7)

Thus, 5/7 - 4/9

= 45/63 - 28/63

= (45 - 28)/63

= 17/63


4. Subtract 5/8 from 1.

Solution:

1 - 5/8

= 1/1 - 5/8

The L.C.M. of the denominators 1 and 8 is 8.

1/1 = (1 × 8)/(1 × 8) = 8/8, (because 8 ÷ 1 = 8)

5/8 = (5 × 1)/(8 × 1) = 5/8, (because 8 ÷ 8 = 1)

Thus, 1/1 - 5/8

= 8/8 - 5/8

= (8 - 5)/8

= 3/8

 

5. Subtract 19/36 from 23/24.

Solution:

23/24 - 19/36

The L.C.M. of the denominators 24 and 36 is 72.

23/24 = (23 × 3)/(24 × 3) = 69/72, (because 72 ÷ 24 = 3)

19/36 = (19 × 2)/(36 × 2) = 38/72, (because 72 ÷ 36 = 2)

Thus, 23/24 - 19/36

= 69/72 - 38/72

= (69 - 38)/72

= 31/72


6. Subtract 9/35 from 3/7.

Solution:

3/7 - 9/35

The L.C.M. of the denominators 7 and 35 is 35.

3/7 = (3 × 5)/(7 × 5) = 15/35, (because 35 ÷ 7 = 5)

9/35 = (9 × 1)/(35 × 1) = 9/35, (because 35 ÷ 35 = 1)

Thus, 3/7 - 9/35

= 15/35 - 9/35

= (15 - 9)/35

= 6/35 

Subtraction of Unlike Fractions


7. Subtract \(\frac{2}{5}\) from 7.

Solution:

\(\frac{7}{1}\) - \(\frac{2}{5}\)

= \(\frac{7  × 5 - 2 × 1}{5}\) LCM of 1 and 5 is 5

= \(\frac{35 -2}{5}\)

= \(\frac{33}{5}\)

= 6\(\frac{3}{5}\)

Hence, 7 - \(\frac{2}{5}\) = 6\(\frac{3}{5}\)


Note: We write the whole number in the fraction form by keeping 1 in the denominator.


Subtraction of Fractions having the Different Denominator:

8. Subtract \(\frac{2}{3}\) - \(\frac{1}{4}\)

\(\frac{2}{3}\) = \(\frac{8}{12}\) [\(\frac{2 × 4}{3 × 4}\) = \(\frac{8}{12}\)]

\(\frac{1}{4}\) = \(\frac{3}{12}\) [\(\frac{1 × 3}{4 × 3}\) = \(\frac{3}{12}\)]

\(\frac{2}{3}\) - \(\frac{1}{4}\) = \(\frac{8}{12}\) - \(\frac{3}{12}\)

= \(\frac{8 - 3}{12}\)

= \(\frac{5}{12}\)

Method 1:

Step I: Find the L.C.M. of the denominators 3 and 4.

L.C.M. of 3 and 4 is 12

Step II: Write the equivalent fractions of \(\frac{2}{3}\) and \(\frac{1}{4}\) with denominator 12.

Step III: Subtract

Step IV: Write the difference in lowest terms.


9. Subtract \(\frac{5}{6}\) - \(\frac{1}{8}\)

\(\frac{5}{6}\) - \(\frac{1}{8}\) = \(\frac{(24 ÷ 6) × 5 – (24 ÷ 8) × 1}{24}\)

= \(\frac{(4 × 5) – (3 × 1)}{24}\)

= \(\frac{20 - 3}{24}\)

= \(\frac{17}{24}\)


Method 2:

L.C.M. of 6 and 8


Subtraction of Mixed Numbers:

Method I:

Subtract 8\(\frac{1}{2}\) - 3\(\frac{1}{4}\)

8\(\frac{1}{2}\) - 3\(\frac{1}{4}\) = (8 – 3) + [\(\frac{1}{2}\) - \(\frac{1}{4}\)]

= 5 + [\(\frac{1}{2}\) - \(\frac{1}{4}\)]

= 5 + [\(\frac{2}{4}\) - \(\frac{1}{4}\)]

= 5 + \(\frac{1}{4}\)

= 5\(\frac{1}{4}\)

Method II:

Subtract 8\(\frac{1}{2}\) - 3\(\frac{1}{4}\)

L.C.M. of 4 and 2 is 4.

8\(\frac{1}{2}\) - 3\(\frac{1}{4}\) = \(\frac{17}{2}\) - \(\frac{13}{4}\)

= \(\frac{34}{4}\) - \(\frac{13}{4}\)

= \(\frac{34 - 13}{4}\)]

= \(\frac{21}{4}\)

= 5\(\frac{1}{4}\)


2. What is 1\(\frac{4}{5}\) less than 4\(\frac{1}{2}\)?

Find 4\(\frac{1}{2}\) - 1\(\frac{4}{5}\)

4\(\frac{1}{2}\) - 1\(\frac{4}{5}\) = \(\frac{9}{2}\) - \(\frac{9}{5}\)            L.C.M. of 2 and 5 is 10.

             = \(\frac{45}{10}\) - \(\frac{18}{10}\)

             = \(\frac{45 - 18}{10}\)

             = \(\frac{27}{10}\)

            = 2\(\frac{7}{10}\)



Questions and Answers on Subtraction of Unlike Fractions:

1. Find the difference:

(i) \(\frac{3}{8}\) - \(\frac{1}{8}\)

(ii) \(\frac{17}{23}\) - \(\frac{6}{23}\)

(iii) \(\frac{1}{2}\) - \(\frac{3}{16}\)

(iv) \(\frac{5}{14}\) - \(\frac{2}{7}\)

(v) \(\frac{5}{6}\) - \(\frac{3}{4}\)

(vi) \(\frac{2}{3}\) - \(\frac{1}{5}\)

(vii) 5 - \(\frac{3}{4}\)

(viii) 2 - \(\frac{15}{21}\)

(ix) 4\(\frac{2}{3}\) - 2



Answers:

1. (i) \(\frac{1}{4}\)

(ii) \(\frac{11}{23}\)

(iii) \(\frac{5}{16}\)

(iv) \(\frac{1}{14}\)

(v) \(\frac{1}{12}\)

(vi) \(\frac{7}{15}\)

(vii) \(\frac{17}{4}\)

(viii) \(\frac{27}{21}\)

(ix) 2\(\frac{2}{3}\)


2. Subtract the following Unlike Fractions:

(i) \(\frac{4}{7}\) - \(\frac{1}{3}\)

(ii) \(\frac{3}{4}\) - \(\frac{1}{2}\)

(iii) 8 - \(\frac{2}{3}\)

(iv) 1\(\frac{5}{6}\) - 1\(\frac{1}{2}\)

(v) 4\(\frac{3}{4}\) - \(\frac{1}{2}\)

(vi) 2\(\frac{1}{3}\) - 1\(\frac{1}{2}\)

(vii) 13\(\frac{4}{7}\) - 6

(viii) 7\(\frac{2}{5}\) - 3\(\frac{1}{2}\)

(ix) \(\frac{9}{2}\) - 4

(x) \(\frac{2}{5}\) - \(\frac{3}{10}\)


Answer: 

2. (i) \(\frac{5}{21}\)

(ii) \(\frac{1}{4}\) 

(iii) 7\(\frac{1}{3}\)

(iv) \(\frac{1}{3}\)

(v) 4\(\frac{1}{4}\)

(vi) \(\frac{5}{6}\)

(vii) 7\(\frac{4}{7}\)

(viii) 3\(\frac{9}{10}\)

(ix) \(\frac{1}{2}\)

(x) \(\frac{1}{10}\)

 Related Concepts




4th Grade Math Activities

From Subtraction of Unlike Fractions to HOME PAGE




Didn't find what you were looking for? Or want to know more information about Math Only Math. Use this Google Search to find what you need.



New! Comments

Have your say about what you just read! Leave me a comment in the box below. Ask a Question or Answer a Question.

Share this page: What’s this?

Recent Articles

  1. Word Problems on Area and Perimeter | Free Worksheet with Answers

    Jul 26, 24 04:58 PM

    word problems on area and perimeter

    Read More

  2. Worksheet on Perimeter | Perimeter of Squares and Rectangle | Answers

    Jul 26, 24 04:37 PM

    Most and Least Perimeter
    Practice the questions given in the worksheet on perimeter. The questions are based on finding the perimeter of the triangle, perimeter of the square, perimeter of rectangle and word problems. I. Find…

    Read More

  3. Perimeter and Area of Irregular Figures | Solved Example Problems

    Jul 26, 24 02:20 PM

    Perimeter of Irregular Figures
    Here we will get the ideas how to solve the problems on finding the perimeter and area of irregular figures. The figure PQRSTU is a hexagon. PS is a diagonal and QY, RO, TX and UZ are the respective d…

    Read More

  4. Perimeter and Area of Plane Figures | Definition of Perimeter and Area

    Jul 26, 24 11:50 AM

    Perimeter of a Triangle
    A plane figure is made of line segments or arcs of curves in a plane. It is a closed figure if the figure begins and ends at the same point. We are familiar with plane figures like squares, rectangles…

    Read More

  5. 5th Grade Math Problems | Table of Contents | Worksheets |Free Answers

    Jul 26, 24 01:35 AM

    In 5th grade math problems you will get all types of examples on different topics along with the solutions. Keeping in mind the mental level of child in Grade 5, every efforts has been made to introdu…

    Read More