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General Form into Normal Form

We will learn the transformation of general form into normal form.

To reduce the general equation Ax + By + C = 0 into normal form (x cos α + y sin α = p):

We have the general equation Ax + By + C = 0.

Let the normal form of the given equation ax + by + c = 0……………. (i) be  

x cos α + y sin α - p = 0, where p > 0. ……………. (ii)

Then, the equations (i) and (ii) are the same straight line i.e., identical.

Acosα = Bsinα = Cp

CP = Acosα = Bsinα = +a2+b2cos2α+sin2α = +  A2+B2

Therefore, p = CA2+B2, cos α = - AA2+B2 and sin α = - BA2+B2

So, putting the values of cos α, sin α and p in the equation (ii) we get the form,

⇒ - AA2+B2 x - BA2+B2 y - CA2+B2 =  0, when c > 0

AA2+B2 x +  BA2+B2 y = - CA2+B2, when c < 0

Which is the required normal form of the general form of equation Ax + By + C = 0.

 

Algorithm to Transform the General Equation to Normal Form

Step I: Transfer the constant term to the right hand side and make it positive.

Step II: Divide both sides by (Coefficient of x)2+(Coefficient of y)2.

The obtained equation will be in the normal form.


Solved examples on transformation of general equation into normal form:

1. Reduce the line 4x + 3y - 19 = 0 to the normal form.

Solution:

The given equation is 4x + 3y - 19 = 0

First shift the constant term (-19) on the RHS and make it positive.

4x + 3y = 19 ………….. (i)

Now determine (Coefficient of x)2+(Coefficient of y)2

= (4)2+(3)2

= 16+9

= √25

= 5

Now dividing both sides of the equation (i) by 5, we get

45x + 35y = 195

Which is the normal form of the given equation 4x + 3y - 19 = 0.

 

2. Transform the equation 3x + 4y = 5√2 to normal form and find the perpendicular distance from the origin of the straight line; also find the angle that the perpendicular makes with the positive direction of the x-axis.

Solution:    

The given equation is 3x + 4y = 5√2 ……..….. (i)

Dividing both sides of equation (1) by + (3)2+(4)2 = + 5 we get,

35x + 45y = 525

35x + 45y = √2

Which is the normal form of the given equation 3x + 4y = 5√2.

Therefore, the required, perpendicular distance from the origin of the straight line (i) is √2 units.

If the perpendicular makes an angle α with the positive direction of the x-axis then,

cos α = 34 and sin α = 45

Therefore, tan α = sinαcosα = 4535 = 43

⇒ α = tan143.

 The Straight Line




11 and 12 Grade Math 

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