Processing math: 100%

Condition of Parallelism of Lines

We will learn how to find the condition of parallelism of lines.

If two lines of slopes m1 and m2 are parallel, then the angle θ between them is of 90°.

Therefore, tan θ = tan 0° = 0

m2m11+m1m2 = 0, [Using tan θ = ± m2m11+m1m2]

m2m1 = 0

⇒ m2 = m1

⇒ m1 = m2

Thus when two lines are parallel, their slopes are equal.

Let, the equations of the straight lines AB and CD are y = m1x+ c1 and y = m2x + c2 respectively.

If the straight lines AB and CD be parallel, then we shall have m1 = m2.

That is the slope of line y = m1 x+ c1  = the slope of the line y = m2x + c2

Conversely, if m1 = m2 then the lines y = m1 x+ c1 and y = m2x + c2 make the same angle with the positive direction of x-axis and hence, the lines are parallel.

 

Solved examples to find the condition of parallelism of two given straight lines:

1. What is the value of k so that the line through (3, k) and (2, 7) is parallel to the line through (-1, 4) and (0, 6)?

Solution:

Let A(3, k), B(2, 7), C(-1, 4)and D(0, 6) be the given points. Then,

m1 = slope of the line AB = 7k23 = 7k1 = k -7

m2 = slope of the line CD = 640(1) = 21 = 2

Since, Ab and CD are parallel, therefore = slope of the line AB = slope of the line CD i.e., m1 = m2.

Thus,

k - 7 = 2

Adding 7 on both sides we get,

K - 7 + 7 = 2 + 7

K = 9

Therefore, the value of k = 9.

 

2. A quadrilateral has the vertices at the points (-4, 2), (2, 6), (8, 5) and (9, -7). Show that the mid-points of the sides of this quadrilateral are the vertices of a parallelogram.

Solution:

Let A(-4, 2), B(2, 6), C(8, 5) and D(9, -7) be the vertices of the given quadrilateral. Let P,Q, R and S be the mid-points of AB, BC, CD and DA respectively. Then the coordinates of P, Q, R and S are P(-1, 4), Q (5, 11/2), R(17/2, -1) and S(5/2, -5/2).

In order to prove that PQRS is a parallelogram, it is sufficient to show that PQ is parallel to RS and PQ =RS.

We have, m1 = Slope of the side PQ = 11245(1)= ¼

m2 = Slope of the side RS = 52+152172 = ¼

Clearly, m1 = m2. This shows that PQ is parallel to RS.

Now, PQ = (5+1)2+(1124)2 = 1532

RS = (52172)2+(52+1)2 = 1532

Therefore, PQ = RS

Thus PQ ∥ RS and PQ = RS.

Hence, PQRS is a parallelogram.

 The Straight Line




11 and 12 Grade Math 

From Condition of Parallelism of Lines to HOME PAGE




Didn't find what you were looking for? Or want to know more information about Math Only Math. Use this Google Search to find what you need.



New! Comments

Have your say about what you just read! Leave me a comment in the box below. Ask a Question or Answer a Question.




Share this page: What’s this?

Recent Articles

  1. 5th Grade Circle Worksheet | Free Worksheet with Answer |Practice Math

    Jul 11, 25 02:14 PM

    Radii of the circRadii, Chords, Diameters, Semi-circles
    In 5th Grade Circle Worksheet you will get different types of questions on parts of a circle, relation between radius and diameter, interior of a circle, exterior of a circle and construction of circl…

    Read More

  2. Construction of a Circle | Working Rules | Step-by-step Explanation |

    Jul 09, 25 01:29 AM

    Parts of a Circle
    Construction of a Circle when the length of its Radius is given. Working Rules | Step I: Open the compass such that its pointer be put on initial point (i.e. O) of ruler / scale and the pencil-end be…

    Read More

  3. Combination of Addition and Subtraction | Mixed Addition & Subtraction

    Jul 08, 25 02:32 PM

    Add and Sub
    We will discuss here about the combination of addition and subtraction. The rules which can be used to solve the sums involving addition (+) and subtraction (-) together are: I: First add

    Read More

  4. Addition & Subtraction Together |Combination of addition & subtraction

    Jul 08, 25 02:23 PM

    Addition and Subtraction Together Problem
    We will solve the different types of problems involving addition and subtraction together. To show the problem involving both addition and subtraction, we first group all the numbers with ‘+’ and…

    Read More

  5. 5th Grade Circle | Radius, Interior and Exterior of a Circle|Worksheet

    Jul 08, 25 09:55 AM

    Semi-circular Region
    A circle is the set of all those point in a plane whose distance from a fixed point remains constant. The fixed point is called the centre of the circle and the constant distance is known

    Read More