Division of Decimal Fractions

The rules of division of decimal fractions by 10, 100, 1000 etc. are discussed here.

(i) While dividing a decimal by 10, 100, or 1000 etc. i.e., multiples of 10, the decimal shifts to the left by as many places as there are zeroes in the divisor.

(ii) If the number of places in the integral part is less, then put the required number of zeroes to the left of the integral part, then shift the decimal point.

1. 71.6 ÷ 10

Solution:

71.6 ÷ 10

716/10 ÷ 10

= 716/10 × 1/10

= 716/100

= 71.6 ÷10

= 7.16

Therefore, 71.6 ÷ 10 = 7.16

Here we observe that decimal moves one place to the left.


2. 923.07 ÷ 100

Solution:

923.07 ÷ 100

= 92307/100 ÷ 100

= 92307/100 × 1/100

= 92307/10000

= 9.2307

Therefore, 923.07 ÷ 100 = 9.2307

Here we observe that decimal shifts two places to the left.



3. 44.008 ÷ 1000

Solution:

44.008 ÷ 1000

44.008/1000 ÷ 1000

= 44008/1000 × 1/1000

= 44008/1000000

=0.044008

Therefore, 44.008 ÷ 1000 = 0.044008

Here we observe that decimal point shifts three places to the left.

Division of Decimal Fractions



Let us consider some of the examples of division of decimal fractions by 10, 100, 1000, etc….

(i) 17.1 ÷ 10

Here the decimal shifts to the left by as many places as there are zeroes in the divisor.

Since there is 1 zero in the divisor then the decimal shifts 1 place to the left.



Therefore, 17.1 ÷ 10 = 1.71


(ii) 42.08 ÷ 10


Since there is 1 zero in the divisor then the decimal shifts 1 place to the left.



Therefore, 42.08 ÷ 10 = 4.208



(iii) 2.1 ÷ 100

We observe that the number of places in the integral part is less, then put the required number of zeroes to the left of the integral part, then shift the decimal point.

Since there are 2 zeroes in the divisor then the decimal shifts 2 places to the left.



Therefore, 2.1 ÷ 100 = 0.021



(iv) 73.3 ÷ 100

We observe that the number of places in the integral part is less, then put the required number of zeroes to the left of the integral part, then shift the decimal point.

Since there are 2 zeroes in the divisor then the decimal shifts 2 places to the left.



Therefore, 73.3 ÷ 100 = 0.733



(v) 81.6 ÷ 1000

We observe that the number of places in the integral part is less, then put the required number of zeroes to the left of the integral part, then shift the decimal point.

Since there are 3 zeroes in the divisor then the decimal shifts 3 places to the left.



Therefore, 81.6 ÷ 1000 = 0.0816



(vi) 984.72 ÷ 1000

We observe that the number of places in the integral part is less, then put the required number of zeroes to the left of the integral part, then shift the decimal point.

Since there are 3 zeroes in the divisor then the decimal shifts 3 places to the left.



Therefore, 984.72 ÷ 1000 = 0.98472


 Choose the right answer and fill in the blank.

(i) 478.65 ÷ ________ = 47.865

(a) 10

(b) 100

(c) 1000

(d) 1

Answer: (a) 10



(ii) 137.85 × 10 = ________

(a) 13785

(b) 13.785

(c) 1378.5

(d) 1.3785

Answer: (c) 1378.5

● Decimal.








5th Grade Numbers Page 

5th Grade Math Problems 

Erom Division of Decimal Fractions to HOME PAGE




Didn't find what you were looking for? Or want to know more information about Math Only Math. Use this Google Search to find what you need.



New! Comments

Have your say about what you just read! Leave me a comment in the box below. Ask a Question or Answer a Question.




Share this page: What’s this?

Recent Articles

  1. 5th Grade Circle Worksheet | Free Worksheet with Answer |Practice Math

    Jul 11, 25 02:14 PM

    Radii of the circRadii, Chords, Diameters, Semi-circles
    In 5th Grade Circle Worksheet you will get different types of questions on parts of a circle, relation between radius and diameter, interior of a circle, exterior of a circle and construction of circl…

    Read More

  2. Construction of a Circle | Working Rules | Step-by-step Explanation |

    Jul 09, 25 01:29 AM

    Parts of a Circle
    Construction of a Circle when the length of its Radius is given. Working Rules | Step I: Open the compass such that its pointer be put on initial point (i.e. O) of ruler / scale and the pencil-end be…

    Read More

  3. Combination of Addition and Subtraction | Mixed Addition & Subtraction

    Jul 08, 25 02:32 PM

    Add and Sub
    We will discuss here about the combination of addition and subtraction. The rules which can be used to solve the sums involving addition (+) and subtraction (-) together are: I: First add

    Read More

  4. Addition & Subtraction Together |Combination of addition & subtraction

    Jul 08, 25 02:23 PM

    Addition and Subtraction Together Problem
    We will solve the different types of problems involving addition and subtraction together. To show the problem involving both addition and subtraction, we first group all the numbers with ‘+’ and…

    Read More

  5. 5th Grade Circle | Radius, Interior and Exterior of a Circle|Worksheet

    Jul 08, 25 09:55 AM

    Semi-circular Region
    A circle is the set of all those point in a plane whose distance from a fixed point remains constant. The fixed point is called the centre of the circle and the constant distance is known

    Read More