Application of Percentage

Application of percentage will help us to apply the procedure to solve real-life percent problems.

Application of percentage:

1. In an election, candidate A got 70 % of the total valid votes. 20 % of the total votes were declared invalid. If the total number of votes is 600000, find the number of valid votes polled in favour of the candidate.

Solution:            

Total number of invalid votes = 20 % of 600000

                                       = 20/100 × 600000

                                       = 120000

Total number of valid votes polled = 600000 - 120000 = 480000

Percentage of valid votes polled in favour of the candidate = 70 %

Therefore Number of valid votes polled in favour of the candidate = 70 % of 480000

= 70/100 × 480000 = 336000 votes

Therefore, the number of valid votes polled in favour of the candidate is 336000.

2. Mother's weight is 25 % more than that of daughter. What percent is daughter's weight less than mother's weight?

Solution:            

Let daughter's weight be 100 kg.

Then mother's weight = (100 + 25) kg = 125 kg

 If mother's weight is 125 kg, then daughter's weight is 100 kg.

If mother's weight is 1 kg, then daughter's weight is 100/125 kg

If mother's weight is 100 kg, then daughter's weight = (100/125 × 100) kg

Therefore, daughter's weight is 20 % less than that of mother.

3. Kelly requires 36 % to pass. She gets 196 marks and falls short by 20 marks. Find the maximum numbers she could have got.

Solution:            

Tanya had scored 20 marks more, she could have scored 36%.

Now, 20 marks more than 196 marks.

Therefore, 196 + 20 = 216

Let maximum marks be x, then 36% of m = 216

⇒ 36/100 × m = 216        

⇒ m = 216 × 100/36

⇒ m = 600

Thus, the maximum marks she could have got were 600.

4. In an examination, 460 students appeared. Out of these students; 23 % got first division, 62 % got second division and the remaining just passed. Assuming that no student failed; find the number of students who just passed.

Solution:

Since, the percentage of first division = 23 %

And, the percentage of second division = 62 %

Therefore, percentage of those who just passed = (100 – 23 – 62) %

                                                                 = (100 – 85) %

                                                                 = 15 %

Therefore, the percentage of those who just passed = 15 % of 460

                                                                      = 15/100 × 460

                                                                      = 6900/100

                                                                      = 69

Fraction into Percentage

Percentage into Fraction

Percentage into Ratio

Ratio into Percentage

Percentage into Decimal

Decimal into Percentage

Percentage of the given Quantity

How much Percentage One Quantity is of Another?

Percentage of a Number

Increase Percentage

Decrease Percentage

Basic Problems on Percentage

Solved Examples on Percentage

Problems on Percentage

Real Life Problems on Percentage

Word Problems on Percentage

Application of Percentage

8th Grade Math Practice

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