Application of percentage will help us to apply the procedure to solve real-life percent problems.

Application of percentage:

**1.** In an election, candidate A got 70 % of the total valid votes. 20 % of the total votes were declared invalid. If the total number of votes is 600000, find the number of valid votes polled in favour of the candidate.

**Solution: **

Total number of invalid votes = 20 % of 600000

= 20/100 × 600000

= 120000

Total number of valid votes polled = 600000 - 120000 = 480000

Percentage of valid votes polled in favour of the candidate = 70 %

Therefore Number of valid votes polled in favour of the candidate = 70 % of 480000

= 70/100 × 480000 = 336000 votes

Therefore, the number of valid votes polled in favour of the candidate is 336000.

**2.** Mother's weight is 25 % more than that of daughter. What percent is
daughter's weight less than mother's weight?

**Solution: **

Let daughter's weight be 100 kg.

Then mother's weight = (100 + 25) kg = 125 kg

If mother's weight is 125 kg, then daughter's weight is 100 kg.

If mother's weight is 1 kg, then daughter's weight is 100/125 kg

If mother's weight is 100 kg, then daughter's weight = (100/125 × 100) kg

Therefore, daughter's weight is 20 % less than that of mother.

**3.** Kelly requires 36 % to pass. She gets 196 marks and falls short by
20 marks. Find the maximum numbers she could have got.

**Solution: **

Tanya had scored 20 marks more, she could have scored 36%.

Now, 20 marks more than 196 marks.

Therefore, 196 + 20 = 216

Let maximum marks be x, then 36% of m = 216

⇒ 36/100 × m = 216

⇒ m = 216 × 100/36

⇒ m = 600

Thus, the maximum marks she could have got were 600.

**4.** In an examination, 460 students appeared. Out of these students; 23
% got first division, 62 % got second division and the remaining just passed.
Assuming that no student failed; find the number of students who just passed.

**Solution:**

Since, the percentage of first division = 23 %

And, the percentage of second division = 62 %

Therefore, percentage of those who just passed = (100 – 23 – 62) %

= (100 – 85) %

= 15 %

Therefore, the percentage of those who just passed = 15 % of 460

= 15/100 × 460

= 6900/100

= 69

Percentage of the given Quantity

How much Percentage One Quantity is of Another?

Real Life Problems on Percentage

**8th Grade Math Practice**

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