Problems on percentage:

**1.** A team lost 25 % of the matches it played. If it won 15 matches, find the number of matches it played.

**Solution:**

Percentage of matches lost = 25 %

Therefore Percentage of matches won (100 - 25) % = 75 %

Let the number of matches played be m.

Then 75 % of m = 15

75/100 × m = 15

m = (15 × 100)/75 %

m = (1500)/75 %

m = 20 %

Therefore, the total number of matches played is 20.

**2.** In a plot of 6000 sq. m., only 4500 sq. m. is allowed for
construction. What percent of the plot is to be left without construction?

**Solution:
**

Percentage of plot allowed for construction = (4500/6000 × 100) % = 75 %.

Thus, the percentage of plot to be left without construction = 100 % - 75 % = 25 %.

**3.** A number is reduced by 100 %. Its present value is 270. What was
its original value?

**Solution:**

Original value is percentage = 100 %.

Reduce amount in percentage = 10 %

Therefore, Percent value in percentage = 100 % - 10 % = 90 %.

According to the problem,

90 % of original value = 270.

Therefore, 100 % of original value = 270/90 × 100 = 300.

Thus, the original value was 300.

**4.** A girl is scored 60 out of 75 in English, 60 out of 90 in
mathematics and 80 out of 100 in Science. Find girls score as percentage:

(i) in Mathematics

(ii) in all the three subjects (on the whole).

**Solution:**

(i) Percentage scored in Mathematics = 60/90 × 100 %

= 6000/90 %

= 200/3 %

= 66(ii) Total maximum of all the three subjects = 75 + 90 + 100 = 265 and

Total score in the three subjects = 60 + 60 + 80 = 200

Therefore, percentage on the whole = (200/265 × 100) %

= (20000/265) %

= 4000/65 %

= 75Percentage of the given Quantity

How much Percentage One Quantity is of Another?

Real Life Problems on Percentage

**8th Grade Math Practice**

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