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Basic Problems on Percentage
Basic problems on percentage will help us to get the basic concept to solve any percentage problems. We will learn how to apply the concept of percentage for solving some real-life problems.
Basic problems on percentage:
1. What is 30 % of 80?
Solution:
30 % of 80
= 30/100 × 80
= (30 × 80)/100
= 2400/100
= 24
2. In a class of 50 students, 40 % are girls. Find the number of girls
and number of boys in the class?
Solution:
Number of girls in the class = 40 % of 50
= 40/100 × 50
= 2000/100
= 20
Number of boys in the class = Total number of students in the class - Number of girls
= 50 – 20
= 30
3. Ron scored 344 marks out of 400 marks and his elder brother Ben scored 582 marks out of 600 marks. Who scored percentage is better?
Solution:
Percentage of marks scored by Ron = (344/400 × 100) %
= (34400/400) %
= (344/4) %
= 86 %
Percentage of marks scored by Ben = (582/600 × 100) %
= (58200/600) %
= (582/6) %
= 97 %
Hence, the percentage marks scored by Ben is better.
4. In final exam of class IX there are 50 students 10 % students failed. How many students passed to class X?
Solution:
Percentage of students passed to class X = 100 % - 10 % = 90 %
90 % of 50
= 90/100 × 50
= 4500/100
= 45
Therefore, 45 students passed to class X.
5. Victor gets 92 % marks in examinations. If these are 460 marks, find the maximum marks.
Solution:
Let the maximum marks be m
Then 92 % of m = 460
⇒ 92/100 × m = 460
⇒ m = (460 × 100)/92
⇒ m = 46000/92
⇒ m = 500
Therefore, maximum marks in the examinations are 500.
Percentage of the given Quantity
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Real Life Problems on Percentage
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