How to find the exact value of tan 22½° using the value of cos 45°?
Solution:
22½° lies in the first quadrant.
Therefore, tan 22½° is positive.
For
all positive values of the angle A we know that, tan \(\frac{A}{2}\) = \(\sqrt{\frac{1 - cos A}{1 + cos A}}\)
tan 22½° = \(\sqrt{\frac{1 - cos 45°}{1 + cos 45°}}\)
tan 22½° = \(\sqrt{\frac{1 - \frac{1}{\sqrt{2}}}{1 + \frac{1}{\sqrt{2}}}}\), [Since we know that cos 45° = \(\frac{1}{\sqrt{2}}\)]
tan 22½° = \(\sqrt{\frac{\sqrt{2} - 1}{\sqrt{2} + 1}}\)
tan 22½° = \(\sqrt{\frac{\sqrt{2} - 1}{\sqrt{2} + 1}\cdot \frac{\sqrt{2} - 1}{\sqrt{2} - 1}}\)
tan 22½° = \(\sqrt{\frac{(\sqrt{2} - 1)^{2}}{2 - 1}}\)
tan 22½° = √2 - 1
Therefore, tan 22½° = √2 - 1
11 and 12 Grade Math
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