We will learn to find the exact value of sin 18 degrees using the formula of multiple angles.
How to find exact value of sin 18°?
Let A = 18°
Therefore, 5A = 90°
⇒ 2A + 3A = 90˚
⇒ 2θ = 90˚ - 3A
Taking sine on both sides, we get
sin 2A = sin (90˚ - 3A) = cos
3A
⇒ 2 sin A
cos
A = 4 cos^3 A - 3 cos A
⇒ 2 sin A
cos
A - 4 cos^3A + 3 cos A
= 0
⇒ cos A (2 sin A - 4 cos^2 A + 3) = 0
Dividing both sides by cos A = cos 18˚ ≠ 0, we get
⇒ 2 sin θ - 4 (1 - sin^2 A) + 3 = 0
⇒ 4 sin^2 A + 2 sin A - 1 = 0, which is a quadratic in sin A
Therefore, sin θ = \(\frac{-2 \pm \sqrt{- 4 (4)(-1)}}{2(4)}\)
⇒ sin θ = \(\frac{-2 \pm \sqrt{4 + 16}}{8}\)
⇒ sin θ = \(\frac{-2 \pm 2 \sqrt{5}}{8}\)
⇒ sin θ = \(\frac{-1 \pm \sqrt{5}}{4}\)
Now sin 18° is positive, as 18° lies in first quadrant.
Therefore, sin 18° = sin A = \(\frac{-1 \pm \sqrt{5}}{4}\)
11 and 12 Grade Math
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