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Circle Touches y-axis

We will learn how to find the equation of a circle touches y-axis.

The equation of a circle with centre at (h, k) and radius equal to a, is (x - h)2 + (y - k)2 = a2.

When the circle touches y-axis i.e., h = a.

Then the equation (x - h)2 + (y - k)2 = a2 becomes  (x - a)2 + (y - k)2 = a2

If a circle touches the y-axis, then the x-co-ordinate of the centre will be equal to the radius of the circle. 

Hence, the equation of the circle will be of the form (x - a)2 + (y - k)2 = a2

Let C (h, k) be the centre of the circle. Since the circle touches the y-axis, therefore, a = h

Hence the equation of the circle is (x - a)2 + (y - k)2 = a2 ⇒ x2 + y2 – 2ax – 2ky + k2 = 0

 

Solved examples on the central form of the equation of a circle touches y-axis:

1. Find the equation of a circle whose y-coordinate of the centre is -7 and radius is 3 units also touches the y-axis.

Solution:

The required equation of the circle whose y-coordinate of the centre is -7 and radius is 3 units also touches the y-axis is (x - 3)2 + (y + 7)2 = 32, [Since radius is equal to the x-coordinate of the centre]

⇒ x2 – 6x + 9 + y2 + 14y + 49 = 9

⇒ x2 + y2 - 6x  + 14y + 49 = 0


2. Find the equation of a circle whose radius is 9 units and y-coordinate of the centre is -6 and also touches the y-axis.

Solution:

The required equation of the circle whose radius is 9 units and y-coordinate of the centre is -6 and also touches the x-axis is (x - 9)2 + (y + 6)2 = 92, [Since radius is equal to the x-coordinate of the centre]

⇒ x2 - 18x + 81 + y2 + 12y + 36 = 81

⇒ x2 + y2 - 18x + 12y + 36 = 0

 The Circle




11 and 12 Grade Math 

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