Word Problems on Multiplication

Word problems on multiplication for fourth grade students are solved here step by step.

Problem Sums Involving Multiplication:

1. 24 folders each has 56 sheets of paper inside them. How many sheets of paper are there altogether?

Solution:

We can add 56 sheets 24 times
OR
Since multiplication is repeated addition we can multiply 56 and 24 to get the answer.

$Word Problems on Multiplication$

[Sometime, more than one calculation is required.]

Therefore, altogether there are 1344 sheets.

2. A carton holds 24 packets of biscuits. Each packet has 12 biscuits. How many biscuits can be packed in 45 cartons?

In one carton we can pack 24 × 12 biscuits.
In 45 cartons, we can pack 24 × 12 × 45 biscuits.
24 × 12 = 288

$Multiplication Word Problems$

→ 40 + 5
Multiply by 5

Multiply by 40

Therefore, altogether there are 12,960 biscuits.

Consider the following Examples on Word Problems Involving Multiplication:

1. A book costs $ 67. How much will be paid for 102 such books?

Solution:

The cost of one book = $ 6 7                   6 7

Number of books = 1 0 2             × 1 0 2

The cost of 102 books = $ 67 × 102        1 3 4

                  = $ 6834         + 6 7 0 0

                                     6 8 3 4

Therefore, cost of 102 books = $ 6834

2. A bicycle costs $ 215. How much will be paid for 87 such bicycles?

Solution:

The cost of one bicycle = $ 2 1 5                   2 1 5

Number of bicycle        = 8 7                       × 8 7

The cost of 87 bicycles        = $ 2 1 5 × 8 7        1 5 0 5

                     = $ 6834            + 1 7 2 0 0

                                           1 8 7 0 5

Therefore, cost of 87 bicycles = $ 18705

3. The monthly salary of a man is $ 2,625. What is his annual income by salary?

Solution:

Monthly income = $2,625 2 6 2 5

Annual income = $2,625 × 12 × 1 2

= $31,500 5 2 5 0

+ 2 6 2 5 0

3 1 5 0 0

Therefore, annual income = $ 31,500

4. A chair costs $ 452 and a table costs $ 1750. What will be cost of 15 chairs and 30 tables?

Solution:

(i) Cost of one chair = $ 452

Cost of 15 chairs = $ 452 × 15

= $ 6,780

(ii) Cost of one table = $ 1,750

Cost of 30 tables = $ 1,750 × 30

= $ 52,500

Therefore, cost of 15 chairs and 30 tables = $ 6,780 + $ 52,500

= $ 59,280

Related Concept

● Addition

● Word Problems on Addition

● Subtraction

● Check for Subtraction and Addition

● Word Problems Involving Addition and Subtraction

● Estimating Sums and Differences

● Find the Missing Digits

● Multiplication

● Multiply a Number by a 2-Digit Number

● Multiplication of a Number by a 3-Digit Number

● Multiply a Number