Word Problems on Multiplication

Word problems on multiplication for fourth grade students are solved here step by step.

Problem Sums Involving Multiplication:

1. 24 folders each has 56 sheets of paper inside them. How many sheets of paper are there altogether?

Solution:

We can add 56 sheets 24 times

OR

Since multiplication is repeated addition we can multiply 56 and 24 to get the answer.

Word Problems on Multiplication

[Sometime, more than one calculation is required.] 

Therefore, altogether there are 1344 sheets. 

2. A carton holds 24 packets of biscuits. Each packet has 12 biscuits. How many biscuits can be packed in 45 cartons? 


In one carton we can pack 24 × 12 biscuits.

In 45 cartons, we can pack 24 × 12 × 45 biscuits.

24 × 12 = 288

Multiplication Word Problems


→ 40 + 5

Multiply by 5

Multiply by 40

Therefore, altogether there are 12,960 biscuits.


Consider the following Examples on Word Problems Involving Multiplication:

1. A book costs $ 67. How much will be paid for 102 such books? 

Solution:

The cost of one book            = $ 6 7                   6 7

Number of books                  = 1 0 2             × 1 0 2

The cost of 102 books          = $ 67 × 102        1 3 4

                                          = $ 6834         + 6 7 0 0

                                                                   6 8 3 4


Therefore, cost of 102 books = $ 6834 


2. A bicycle costs $ 215. How much will be paid for 87 such bicycles? 

Solution: 

The cost of one bicycle            = $ 2 1 5                   2 1 5

Number of bicycle                    = 8 7                       × 8 7

The cost of 87 bicycles            = $ 2 1 5 × 8 7        1 5 0 5

                                             = $ 6834            + 1 7 2 0 0

                                                                          1 8 7 0 5

Therefore, cost of 87 bicycles = $ 18705


3. The monthly salary of a man is $ 2,625. What is his annual income by salary? 


Solution:

Monthly income               = $2,625                   2 6 2 5

Annual income                 = $2,625 × 12             × 1 2
  
                                      = $31,500                 5 2 5 0

                                                                + 2 6 2 5 0

                                                                    3 1 5 0 0

Therefore, annual income = $ 31,500



4. A chair costs $ 452 and a table costs $ 1750. What will be cost of 15 chairs and 30 tables? 


Solution:

(i) Cost of one chair         = $ 452

Cost of 15 chairs             = $ 452 × 15

                                    = $ 6,780


(ii) Cost of one table        = $ 1,750

Cost of 30 tables             = $ 1,750 × 30

                                    = $ 52,500

Therefore, cost of 15 chairs and 30 tables = $ 6,780 + $ 52,500

Related Concept

Addition

Word Problems on Addition

Subtraction

Check for Subtraction and Addition

Word Problems Involving Addition and Subtraction

Estimating Sums and Differences

Find the Missing Digits

Multiplication

Multiply a Number by a 2-Digit Number

Multiplication of a Number by a 3-Digit Number

Multiply a Number

Estimating Products

Word Problems on Multiplication

Multiplication and Division

Terms Used in Division

Division of Two-Digit by a One-Digit Numbers

Division of Four-Digit by a One-Digit Numbers

Division by 10 and 100 and 1000

Dividing Numbers

Estimating the Quotient

Division by Two-Digit Numbers

Word Problems on Division





4th Grade Math Activities

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