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We will learn step-by-step the proof of compound angle formula sin2 α - sin2 β. We need to take the help of the formula of sin (α + β) and sin (α - β) to proof the formula of sin2 α - sin2 β for any positive or negative values of α and β.
Prove that sin (α + β) sin (α - β) = sin2 α - sin2 β = cos2 β - cos2 α.
Proof: sin(α + β) sin (α + β)
= (sin α cos β + cos α sin β) (sin α cos β - cos α sin β); [applying the formula of sin (α + β) and sin (α - β)]
= (sin α cos β)2 - (cos α sin β)2
= sin2 α cos2 β - cos2 α sin2 β
= sin2 α (1 - sin2 β) - (1 - sin2 α) sin2 β; [since we know, cos2 θ = 1 - sin2 θ]
= sin2 α
- sin2 α sin2 β - sin2 β + sin2 α sin2 β
= sin2 α - sin2 β
= 1 - cos2 α - (1 - cos2 β); [since we know, sin2 θ = 1 - cos2 θ]
= 1 - cos2 α - 1 + cos2 β
= cos2 β - cos2 α Proved
Therefore, sin (α + β) sin (α - β) = sin2 α - sin2 β = cos2 β - cos2 α
Solved examples using the proof of compound angle formula sin2 α - sin2 β:
1. Prove that sin2 6x - sin2 4x = sin 2x sin 10x.
Solution:
L.H.S. = sin2 6x - sin2 4x
= sin (6x + 4x) sin (6x - 4x); [since we know sin2 α - sin2 β = sin (α + β) sin (α - β)]
= sin 10x sin 2x = R.H.S. Proved
2. Prove that cos2 2x - cos2 6x = sin 4x sin 8x.
Solution:
L.H.S. = cos2 2x - cos2 6x
= (1 - sin2 2x) - (1 - sin2 6x), [since we know cos2 θ = 1 - sin2 θ]
= 1 - sin2 2x - 1 + sin2 6x
= sin2 6x - sin2 2x
= sin (6x + 2x) sin (6x - 2x), [since we know sin2 α - sin2 β = sin (α + β) sin (α - β)]
= sin 8x sin 4x = R.H.S. Proved
3. Evaluate: sin2 (π8 + x2) - sin2 (π8 - x2).
Solution:
sin2 (π8 + x2) - sin2 (π8 - x2)
= sin {(π8 + x2) + (π8 - x2)} sin {(π8 + x2) - (π8 - x2)}, [since we know sin2 α - sin2 β = sin (α + β) sin (α - β)]
= sin {π8 + x2 + π8 - x2} sin {π8 + x2 - π8 + x2}
= sin {π8 + π8} sin {x2 + x2}
= sin π4 sin x
= 1√2 sin x, [Since we know sin π4 = 1√2]
11 and 12 Grade Math
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