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We will learn how to prove the property of the inverse trigonometric function 2 arcsin(x) = arcsin(2x√1−x2) or, 2 sin−1 x = sin−1 (2x√1−x2).
Proof:
Let, sin−1 x = α
Therefore, sin α = x
Now, sin 2α = 2 sin α cos α
sin 2α = 2 sin α \sqrt{1 - sin^{2}α}
sin 2α = 2x . \sqrt{1 - x^{2}}
sin 2α = 2x\sqrt{1 - x^{2}}
Therefore, 2α = sin^{-1} (2x\sqrt{1 - x^{2}})
2 sin^{-1} x = sin^{-1} (2x\sqrt{1 - x^{2}}).
or, 2 arcsin(x) = arcsin(2x\sqrt{1 - x^{2}}) Proved
● Inverse Trigonometric Functions
11 and 12 Grade Math
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