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We will learn how to prove the property of the inverse trigonometric function arctan(x) + arccot(x) = π2 (i.e., tan−1 x + cot−1 x = π2).
Proof: Let, tan−1 x = θ
Therefore, x = tan θ
x = cot (π2 - θ), [Since, cot (π2 - θ) = tan θ]
⇒ cot−1 x = π2 - θ
⇒ cot−1 x= π2 - tan−1 x, [Since, θ = tan−1 x]
⇒ cot−1 x + tan−1 x = π2
⇒ tan−1 x + cot−1 x = π2
Therefore, tan−1 x + cot−1 x = π2. Proved.
Solved examples on property of inverse
circular function tan−1 x + cot−1 x =
π2
Prove that, tan−1 4/3 + tan−1 12/5 = π - tan−1 5633.
Solution:
We know that tan−1 x + cot−1 x = π2
⇒ tan−1 x = π2 - cot−1 x
⇒ tan−1 43 = π2 - cot−1 43
and
tan−1 125 = π2 - cot−1 125
Now, L. H. S. = tan−1 43 + tan−1 125
= π2 - cot−1 43 + π2 - cot−1 125, [Since, tan−1 43 = π2 - cot−1 43 and tan−1 125 = π2 - cot−1 125]
= π - (cot−1 43 + cot−1 125)
= π - (tan−1 34 + tan−1 512)
= π – tan−1 34+5121–34·512
= π – tan−1 (1412 x 4833)
= π – tan−1 5633 = R. H. S. Proved.
● Inverse Trigonometric Functions
11 and 12 Grade Math
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