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arccot(x) - arccot(y) = arccot(xy+1yβˆ’x)

We will learn how to prove the property of the inverse trigonometric function arccot(x) - arccot(y) = arccot(xy+1yβˆ’x) (i.e., cotβˆ’1 x + cotβˆ’1 y = cotβˆ’1 (xy+yyβˆ’x)

Proof:

Let, cotβˆ’1 x = Ξ± and cotβˆ’1 y = Ξ²

From cotβˆ’1 x = Ξ± we get,

x = cot Ξ±

and from cotβˆ’1 y = Ξ² we get,

y = cot Ξ²

Now, cot (Ξ± - Ξ²) = (cotΞ±cotΞ²+1cotΞ²βˆ’tanΞ±)

cot (Ξ± - Ξ²) = xy+1yβˆ’x

β‡’ Ξ± - Ξ² = cotβˆ’1 xy+1yβˆ’x

β‡’ cotβˆ’1 x - cotβˆ’1 y = cotβˆ’1 xy+1yβˆ’x

Therefore, cotβˆ’1 x - cotβˆ’1 y = cotβˆ’1 xy+1yβˆ’x

● Inverse Trigonometric Functions








11 and 12 Grade Math

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