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arcsin (x) + arcsin(y) = arcsin (x 1y2 + y1x2)

We will learn how to prove the property of the inverse trigonometric function arcsin (x) + arcsin(y) = arcsin (x 1y2 + y1x2)

Proof:  

Let, sin1 x = α and sin1 y = β

From sin1 x = α we get,

x = sin α

and from sin1 y = β we get,

y = sin β

Now, sin (α + β) = sin α cos β + cos α sin β

sin (α + β) = sin α 1sin2β + 1sin2α sin β

sin (α + β) = x ∙ 1y2 + 1x2 ∙ y

Therefore, α + β = sin1 (x 1y2 + y1x2

or, sin1 x + sin1 y = sin1 (x 1y2 + y1x2).       Proved.


Note: If x > 0, y > 0 and x2 + y2 > 1, then the sin1 x + sin1 y may be an angle more than π/2 while sin1 (x 1y2 + y1x2), is an angle between – π/2 and π/2.

Therefore, sin1 x + sin1 y = π - sin1 (x 1y2 + y1x2)



1. Prove that sin1 35 + sin1 817 = sin1 7785

Solution:

L. H. S. = sin1 35 + sin1 817

Now, we will apply the formula sin1 x + sin1 y = sin1 (x 1y2 + y1x2)

= sin1 (35 1(817)2 + 8171(35)2)

= sin1 (35 ×  1517 + 817 ×  45)

= sin1  7785 = R. H. S.                  Proved.


2. Show that, sin1 45 + sin1 513 + sin1 1665 = π2.  

Solution:     

L. H. S. = (sin145 + sin1513) + sin11665

Now, we will apply the formula sin1 x + sin1 y = sin1 (x1y2 + y1x2)

= sin1 (45 1(513)2 + 5131(45)2 + sin11665

= sin1 (45 ×  1213 + 513 ×  35) + sin11665

= sin1 6365 + sin11665

= sin1 6365 + cos16365, [Since, sin1 1665 = cos1 6365]

= π2, [Since, sin1 x + cos1 x = π2] = R. H. S.            Proved.


Note: sin1 = arcsin (x)

 Inverse Trigonometric Functions






11 and 12 Grade Math

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