We will learn how to prove the property of the inverse trigonometric function 3 arccos(x) = arccos(4x\(^{3}\) - 3x) or, 3 cos\(^{-1}\) x = cos\(^{-1}\) (4x\(^{3}\) - 3x)
Proof:
Let, cos\(^{-1}\) x = θ
Therefore, cos θ = x
Now we know that, sin 3θ = 4 cos\(^{3}\) θ - 3 cos θ
⇒ cos 3θ = 4x\(^{3}\) - 3x
Therefore, 3θ = cos\(^{-1}\) (4x\(^{3}\) - 3x)
⇒ 3 cos\(^{-1}\) x = cos\(^{-1}\) (4x\(^{3}\) - 3x)
or, 3 arccos(x) = arccos(4x\(^{3}\) - 3x). Proved.
● Inverse Trigonometric Functions
11 and 12 Grade Math
From 3 arccos(x) to HOME PAGE
Didn't find what you were looking for? Or want to know more information about Math Only Math. Use this Google Search to find what you need.
Dec 14, 24 02:12 PM
Dec 14, 24 12:25 PM
Dec 13, 24 08:43 AM
Dec 13, 24 12:31 AM
Dec 12, 24 11:22 PM
New! Comments
Have your say about what you just read! Leave me a comment in the box below. Ask a Question or Answer a Question.