Examples on Quadratic Equations

We will discuss here about some examples on quadratic equations.

We know many word problems involving unknown quantities can be translated into quadratic equations in one unknown quantity.


1. Two pipes working together can fill a tank in 35 minutes. If the large pipe alone can fill the tank in 24 minutes less than the time taken by the smaller pipe then find the time taken by each pipe working alone to fill the tank.

Solution:

Let the large pipe and smaller pipe working alone fill the tank in x minutes and y minutes respectively.

Therefore, the large pipe fills \(\frac{1}{x}\) of the tank in 1 minute and the smaller pipe fills \(\frac{1}{y}\) of the tank in 1 minute.


Therefore, two pipes working together can fill (\(\frac{1}{x}\) + \(\frac{1}{y}\)) of the tank in 1 minute.

Therefore, two pipes working together can fill 35(\(\frac{1}{x}\) + \(\frac{1}{y}\)) of the tank in 35 minutes.

From the question, 35(\(\frac{1}{x}\) + \(\frac{1}{y}\)) = 1 (whole being 1). ......................... (i)

Also, x + 24 =y (from the question). ......................... (ii)

Putting y = x + 24 in (i), 35(\(\frac{1}{x}\) + \(\frac{1}{x + 24}\)) = 1

⟹ 35\(\frac{x + 24 + x}{x(x + 24)}\) = 1

⟹ \(\frac{35(2x + 24)}{x(x + 24)}\) = 1

⟹ 35(2x + 24) = x(x + 24)

⟹ 70x + 35 × 24 = x\(^{2}\) + 24x

⟹ x\(^{2}\) - 46x - 840 = 0

⟹ x\(^{2}\) – 60x + 14x – 840 = 0

⟹ x(x - 60) + 14(x - 60) = 0

⟹ (x - 60)(x + 14) = 0

⟹ x - 60 = 0 or, x + 14 = 0

⟹ x = 60 or x = -14

But x cannot be negative. So, x = 60 and then y = x + 24 = 60 + 24 = 84.

Therefore, when working alone, the large pipe takes 60 minutes and the smaller pipe takes 84 minutes to fill the tank.

  

2. Find a positive number, which is less than its square by 30.

Solution:

Let the number be x

By the condition, x\(^{2}\) - x = 30

⟹ x\(^{2}\) - x - 30 = 0

⟹ (x - 6)(x + 5) = 0

⟹ Therefore,  x = 6, -5

As the number is positive, x = - 5 is not acceptable, Thus the required number is 6.


3. The product of the digits of a two-digit number is 12. If 36 is added to the number, a number is obtained which is the same as the number obtained by reversing the digits of the original number.

Solution:

Let the digit at the units place be x and that at the tens place be y.

Then, the number = 10y + x.

The number obtained by reversing the digits = 10x + y

From the question, xy = 12 ................... (i)

10y + x + 36 = 10x + y ........................... (ii)

From (ii), 9y - 9x + 36 = 0

⟹ y – x + 4 =0

⟹ y = x – 4 .................................. (iiii)

Putting y = x- 4 in (i), x(x – 4) =12

⟹ x\(^{2}\) – 4x – 12 = 0

⟹ x\(^{2}\) – 6x + 2x – 12 = 0

⟹ x(x – 6) + 2(x – 6) = 0

⟹ (x – 6)(x + 2) = 0

⟹ x – 6 = 0 or x + 2 = 0

⟹ x = 6 or x = -2

But a digit in a number cannot be negative. So, x ≠ -2.

Therefore, x = 6.

Therefore, from (iii), y = x – 4 = 6 – 4 = 2.

Thus, the original number 10y + x = 10 × 2 + 6 = 20 + 6 = 26.

 

4. After completing a journey of 84 km. A cyclist noticed that he would take 5 hours less, if he could travel at a speed which is 5 km/hour more. What was the speed of cyclist in km/hour?

Solution:

Suppose, the cyclist has travelled with a speed of x km/hour

Therefore, by the condition \(\frac{84}{x}\) - \(\frac{84}{x + 5}\) = 5

⟹ \(\frac{84x + 420 - 84x}{x(x + 5)}\)= 5

⟹ \(\frac{420}{x^{2} + 5x}\) = 5

⟹ 5(x\(^{2}\) + 5x) = 420

⟹ x\(^{2}\) + 5x - 84 = 0

⟹ (x + 12)(x - 7) = 0

Therefore, x = -12, 7

But x ≠- 12, because speed cannot be negative

x = 7

Therefore, the cyclist has travelled with a speed of 7 km/hour.

Quadratic Equation

Introduction to Quadratic Equation

Formation of Quadratic Equation in One Variable

Solving Quadratic Equations

General Properties of Quadratic Equation

Methods of Solving Quadratic Equations

Roots of a Quadratic Equation

Examine the Roots of a Quadratic Equation

Problems on Quadratic Equations

Quadratic Equations by Factoring

Word Problems Using Quadratic Formula

Examples on Quadratic Equations 

Word Problems on Quadratic Equations by Factoring

Worksheet on Formation of Quadratic Equation in One Variable

Worksheet on Quadratic Formula

Worksheet on Nature of the Roots of a Quadratic Equation

Worksheet on Word Problems on Quadratic Equations by Factoring







9th Grade Math

From Examples on Quadratic Equations to HOME PAGE




Didn't find what you were looking for? Or want to know more information about Math Only Math. Use this Google Search to find what you need.



Share this page: What’s this?

Recent Articles

  1. Dividing 3-Digit by 1-Digit Number | Long Division |Worksheet Answer

    Apr 24, 24 03:46 PM

    Dividing 3-Digit by 1-Digit Number
    Dividing 3-Digit by 1-Digit Numbers are discussed here step-by-step. How to divide 3-digit numbers by single-digit numbers? Let us follow the examples to learn to divide 3-digit number by one-digit nu…

    Read More

  2. Symmetrical Shapes | One, Two, Three, Four & Many-line Symmetry

    Apr 24, 24 03:45 PM

    Symmetrical Figures
    Symmetrical shapes are discussed here in this topic. Any object or shape which can be cut in two equal halves in such a way that both the parts are exactly the same is called symmetrical. The line whi…

    Read More

  3. Mental Math on Geometrical Shapes | Geometry Worksheets| Answer

    Apr 24, 24 03:35 PM

    In mental math on geometrical shapes we will solve different type of problems on simple closed curves, polygons, basic geometrical concepts, perpendicular lines, parallel lines, circle, terms relates…

    Read More

  4. Circle Math | Terms Related to the Circle | Symbol of Circle O | Math

    Apr 24, 24 02:57 PM

    Circle using a Compass
    In circle math the terms related to the circle are discussed here. A circle is such a closed curve whose every point is equidistant from a fixed point called its centre. The symbol of circle is O. We…

    Read More

  5. Fundamental Geometrical Concepts | Point | Line | Properties of Lines

    Apr 24, 24 12:38 PM

    Point P
    The fundamental geometrical concepts depend on three basic concepts — point, line and plane. The terms cannot be precisely defined. However, the meanings of these terms are explained through examples.

    Read More