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In addition of capacity we will learn how to add the different units of capacity and volume together. While adding we need to follow that the units of capacity i.e., liter and milliliter are converted into milliliters before addition and then follow the simple addition process.
We will learn two different methods to solve addition using the standard unit and smaller unit of capacity. Students can practice both the methods.
(i) Adding units with conversion into milliliters
(ii) Adding units without conversion into milliliters
We can add two or more units of capacity β and mβ just like ordinary numbers.
Worked-out Examples on Addition of Capacity and Volume:
1. Add 3 β 600 mβ and 6 β 300 mβ
Solution:
Method I: (with conversion into milliliters):
We know, 1 liter = 1000 milliliters
Now liter (β) and milliliters (mβ) are converted into mβ before doing addition and then we need to follow the simple addition process.
3 β 600 mβ = (3 Γ 1000) mβ + 600 mβ
= 3000 mβ + 600 mβ
= 3600 milliliters
6 β 300 mβ = (6 Γ 1000) mβ + 300 mβ
= 6000 mβ + 300 mβ
= 6300 milliliters
Now sum,
3600 mβ
+ 6300 mβ
9900 mβ
= 9 β 900 mβ
Therefore, 3 β 600 mβ + 6 β 300 mβ = 9 β 900 mβ.
Method II: (without conversion into milliliters):
Here β and mβ are arranged in different columns and then added like ordinary numbers.
(i) β and mβ are arranged column-wise
(ii) 600 mβ + 300 mβ = 900 mβ
(iii) 3 β + 6 β = 9 β
β mβ
3 600
+ 6 300
9 900
= 9 β 900 mβ
Therefore, sum of 3 β 600 mβ and 6 β 300 mβ = 9 β 900 mβ.
2. Add 5 β 725 mβ and 8 β 450 mβ
Solution:
Method I: (with conversion into milliliters):
We know, 1 liter = 1000 milliliters
Now liter (β) and milliliters (mβ) are converted into ml before doing addition and then we need to follow the simple addition process.
5 β 725 mβ = (5 Γ 1000) mβ + 725 mβ
= 5000 mβ + 725 mβ
= 5725 milliliters
8 β 450 mβ = (8 Γ 1000) mβ + 450 mβ
= 8000 mβ + 450 mβ
= 8450 milliliters
Now sum,
1
5725 mβ
+ 8450 mβ
14175 mβ
= 14 β 175 mβ
Therefore, 5 β 725 mβ + 8 β 450 mβ = 14 β 175 mβ
Method II: (without conversion into milliliters):
Here β and mβ are arranged in different columns and then added like ordinary numbers.
(i) β and mβ are arranged column-wise
(ii) 725 mβ + 450 mβ = 1 β 175 mβ.
175 mβ is placed under mβ. 1 β is taken in β column.
(iii) 1 β + 5 β + 8 β = 14 β
β mβ
1
5 725
+ 8 450
14 175
= 14 β 175 mβ
Therefore, sum of 5 β 725 mβ and 8 β 450 mβ = 14 β 175 mβ.
More solved examples on addition of capacity where the method is mentioned in the given question.
3. Add 17 β 387 mβ, 7 β 750 mβ and 9 β without conversion into milliliters.
Solution:
Without conversion into milliliters here β and mβ are arranged in different columns and then added like ordinary numbers.
(i) β and mβ are arranged column-wise
(ii) 387 mβ + 750 mβ = 1 β 137 mβ.
137 mβ is placed under mβ. 1 β is taken in β column.
(iii) 1 β + 17 β + 7 β + 9 β = 34 β
β mβ
21 1
17 387
7 750
+ 9 000
34 137
= 34 β 137 mβ
Therefore, sum of 17 β 387 mβ, 7 β 750 mβ and 9 β = 34 β 137 mβ.
4. Add 13 β 250 mβ, 8 β 750 mβ and 6 β with conversion into milliliters
Solution:
With conversion into milliliters here we will do the addition process.
We know, 1 liter = 1000 milliliters
Now liter (β) and milliliters (mβ) are converted into ml before doing addition and then we need to follow the simple addition process.
13 β 250 mβ = (13 Γ 1000) mβ + 250 mβ
= 13000 mβ + 250 mβ
= 13250 milliliters
8 β 750 mβ = (8 Γ 1000) mβ + 750 mβ
= 8000 mβ + 750 mβ
= 8750 milliliters
6 β = (6 Γ 1000) mβ
= 6000 milliliters
Now sum,
111
13250 mβ
8750 mβ
+ 6000 mβ
28000 mβ
= 28 β 000 mβ
= 28000 mβ
Therefore, 13 β 250 mβ + 8 β 750 mβ + 6 β = 28000 mβ
5. Add 36 β 275 mβ and 16 β 150 mβ.
|
Solution: Arrange the numbers vertically. First, add the milliliters. 275 mβ + 150 mβ = 425 mβ Add the liters 36 β + 16 β = 52 β |
Hence, 36 β 275 mβ + 16 β 150 mβ = 52 β 425 mβ
6. Add 150 β 810 mβ and 90 β 300 mβ
Solution:
|
Arrange the numbers vertically. First, add the milliliters. 810 mβ + 300 mβ = 1110 mβ = 1 β 110 mβ Write 110 under mβ column and carry over 1 β to the liters column. Add the liters 150 β + 90 β + 1 = 241 β |
Hence, 150 β 810 mβ + 90 β 300 mβ = 241 βl 110 mβ
For addition, write the number of mβ and β in separate columns then add like ordinary numbers. starting from the right.
7. Add 27 β 450 mβ & 52 β 120 mβ.
Solution:
mβ β
27 450
+ 52 120
79 570
Answer: 79 mβ 570 mβ
8. Add 214 β 321 mβ, 426 β 932 mβ & 358 β 416 mβ.
Solution:
mβ β
1 1
2 1 4 3 2 1
4 2 6 9 3 2
+ 3 5 8 4 1 6
9 9 9 6 6 9
Answer: 999 mβ 669 mβ
9. Find the sum of the capacity: 28 β 32 mβ + 73 β 68 mβ
|
Solution: 28 β 32 mβ + 73 β 68 mβ First add mβ = 32 mβ + 68 mβ = 100 mβ Now add liters = 28 β + 93 β = 121 β |
Therefore, required sum = 121 β 100 mβ
10. Find the sum of the capacities 1 β 900 mβ, 10 β 50 mβ and 15 β 732 mβ.
Solution:
Step I: Write the volumes to be added in β and mβ columns as shown.
Step II: Add the millilitres.
Step III: Then add the litres.
Remember to add the carry overs.
Therefore, the answer is 27 β 682 mβ.
Word Problems on Addition of Capacity and Volume:
ADDITION OF LITRES AND MILLILITRES
11. Finn purchased 3 β 250 mβ of milk on Monday, 2 β 750 mβ on Wednesday and 3 β 500 mβ on Friday. How much milk did Finn purchased during these three days?
Solution:
1 1
Milk purchased on Monday = 3 β 250 mβ
Milk purchased on Wednesday = 2 β 750 mβ
Milk purchased on Friday = 3 β 500 mβ
+
Therefore, total milk purchased during these 3 days = 9 β 500 mβ
12. Nisha poured 5 litres 250 millilitres of water in a bucket. Tanya poured 6 litres 500 millilitres of water in the same bucket. How much water is there in the bucket now?
Solution:
Write β and mβ in columns as shown.
|
Step I: Add mβ first. 250 + 500 = 750 Write 750 in the mβ column. Step II: Add β now. 5 + 6 = 11 Write 11 in the β column. |
Therefore, the total quantity of water in the bucket is 11 β 750 mβ.
The above problems on addition of capacity will help the students to practice the worksheet on adding the different units with conversion or without conversion.
I. Add the following:
(i) 7 β 152 mβ + 2 β 339 mβ
(ii) 5 β 240 mβ + 7 β 860 mβ
(iii) 70 β 000 mβ + 22 β 504 mβ
(iv) 13 β 1290 mβ + 18 β 160 mβ
(v) 32 β 540 mβ + 18 β + 210 mβ
(vi) 19 β 300 mβ + 3 β 900 mβ
(vii) 62 β 200 mβ + 15 mβ 385 mβ
(viii) 120 β + 625 mβ + 30 β 750 mβ
(ix) 21 β 845 mβ + 32 β 116 mβ + 38 β 082 mβ
Answers:
I. (i) 9 l 491 ml
(ii) 13 l 100 ml
(iii) 92 l 504 ml
(iv) 31 l 450 ml
(v) 50 l 750 ml
(vi) 23 l 200 ml
(vii) 77 l 585 ml
(viii) 151 l 375 ml
(ix) 92 l 43 ml
II. Add the following:
|
(i) |
mβ β 21 27 + 48 32 _ _______ _ |
(ii) |
mβ β 86 45 + 12 20 _ _______ _ |
|
(iii) |
mβ β 27 10 + 11 25 _ _______ _ |
(iv) |
mβ β 32 94 + 60 05 _ _______ _ |
|
(v) |
mβ β 17 826 + 23 578 _ _______ __ |
(vi) |
mβ β 46 950 + 39 475 _ ________ _ |
|
(vii) |
mβ β 76 586 + 45 674 _ _______ __ |
(viii) |
mβ β 51 700 + 48 300 _ ________ _ |
|
(ix) |
mβ β 209 68 214 09 + 116 00 _ _______ __ |
(x) |
mβ β 423 00 147 05 + 208 79 _ _______ __ |
|
(xi) |
mβ β 126 90 103 70 + 264 50 _ _______ __ |
(xii) |
mβ β 210 73 216 08 + 205 98 _ _______ __ |
|
(xiii) |
mβ β 205 853 369 786 + 8 678 _ ________ __ |
(xiv) |
mβ β 125 675 465 850 + 310 625 _ ________ __ |
|
(xv) |
mβ β 318 564 237 658 + 8 678 _ ________ __ |
(xvi) |
mβ β 275 750 117 650 + 10 545 _ ________ __ |
Answer:
2. (i) 69 β 59 mβ
(ii) 98 β 65 mβ
(iii) 38 β 35 mβ
(iv) 92 β 99 mβ
(v) 41 β 404 mβ
(vi) 86 β 425 mβ
(vii) 122 β 260 mβ
(viii) 100 β 00 mβ
(ix) 53 β 977 mβ
(x) 77 β 884 mβ
(xi) 49 β 510 mβ
(xii) 63 β 279 mβ
(xiii) 584 β 317 mβ
(xiv) 902 β 150 mβ
(xv) 564 β 600 mβ
(xvi) 403 β 945 mβ
β Related Concepts
β Conversion of Standard Unit of Capacity
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