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We will learn Addition of 3-Digit Numbers without Regrouping.
Addition without regrouping means adding numbers together without carrying any digit to the next place value.
In this method:
Since the sum in each column is less than 10, no carrying is needed.
For Example:
246 + 132= 378
Here:
No digit is carried to the next column, so this is called addition without regrouping.
Addition without regrouping is adding numbers without carrying over any number to the next place value.
We know how to do addition of 3-digit numbers without regrouping. Let us recall it solving some examples.
1. Add 572 and 424.
H T O
5 7 2 → 5 hundreds + 7 tens + 2 ones
+ 4 2 4 → 4 hundreds + 2 tens + 4 ones
9 9 6 → 9 hundreds + 9 tens + 6 ones
2. The shopkeeper has 153 packets of chocolate cookies and 124 butter cookies. How many cookies are there in all?
|
Solution: To find out the total number of cookies, we will perform addition. Step 1: First add the ones. 3 + 4 = 7 Step 2: Next add the tens. 5 + 2 = 7 Step 3: Then, add the hundreds. 1 + 1 = 2 |
Thus, there are 277 cookies in the shop. |
3. Add 641 and 325.
Solution:
|
Step 1: Arrange the numbers vertically. Step 2: First add the ones. 1 + 5 = 6 Step 3: Now, add the tens. 4 + 2 = 6 Lastly, add the hundreds. 6 + 3 = 9 |
Thus, 641 + 325 = 966 |
4. Let us add 451 and 246.
Solution:
Write the numbers one below the other.
Step I: Add the ones.
1 one + 6 ones = 7 ones
Write 7 in the ones place.
Step II: Add the tens.
5 tens + 4 tens = 9 tens
Write 9 in the tens place.
Step III: Add the hundreds.
4 hundreds + 2 hundreds = 6 hundreds
Write 6 in the hundreds place.
The sum is 697.
4. Add 245 and 132.
Step I: Arrange the two numbers in hundreds, tens and ones.
Thus, 245 + 132 = 377
Your Final Score: 0
We will add three 3-digit numbers in the same way as we add two 3-digit numbers.
For examples:
|
5. Add 542, 234 and 103. Solution: Step 1: Arrange the numbers vertically. Step 2: First add the ones. 2 + 4 + 3 = 9 Step 3: Now, add the tens. 4 + 3 + 0 = 7 Step 4: Lastly, add the hundreds. 5 + 2 + 1 = 8 |
![]() Thus, 542 + 234 + 103 = 879 |
6. On the 'World Environment Day' class I planted 146 saplings and class II planted 433 saplings. How many saplings did they plant in all?
Solution:
146 + 433 = ?
So, they planted 579 saplings in all.
7. There were 136 people in one compartment of train and 122 people in another compartment. How many people in the both compartments?
Solution:
H T O
1 3 6
+ 1 2 2
2 5 8
Thus, there were 258 people in all.
I. Add the following:
(i) 452 + 7
(ii) 238 + 61
(iii) 601 + 25
(iv) 758 + 31
(v) 604 + 33
(vi) 576 + 12
(vii) 934 + 40
(viii) 457 + 22
(ix) 460 + 506
(x) 251 + 238
(xi) 261 + 437
(xii) 384 + 112
(xiii) 708 + 191
(xiv) 348 + 321
(xv) 709 + 190
(xvi) 652 + 246
(xvii) 230 + 367
(xviii) 323 + 475
(xix) 832 + 131
(xx) 450 + 238
Answer:
I. (i) 459
(ii) 299
(iii) 626
(iv) 789
(v) 637
(vi) 588
(vii) 974
(viii) 479
(ix) 966
(x) 489
(xi) 698
(xii) 496
(xiii) 899
(xiv) 669
(xv) 899
(xvi) 898
(xvii) 597
(xviii) 798
(xix) 963
(xx) 688
II. Add the following and fill in the blanks:
(i) 503 + 6 = __________
(ii) 142 + 7 = __________
(iii) 674 + 23 = __________
(iv) 256 + 42 = __________
(v) 725 + 214 = __________
(vi) 345 + 153 = __________
(vii) 854 + 144 = __________
(viii) 615 + 212 = __________
(ix) 600 + 199 = __________
Answer:
II. (i) 503 + 6 = __________
(ii) 142 + 7 = __________
(iii) 674 + 23 = __________
(iv) 256 + 42 = __________
(v) 725 + 214 = __________
(vi) 345 + 153 = __________
(vii) 854 + 144 = __________
(viii) 615 + 212 = __________
(ix) 600 + 199 = __________
III. Add the following
(i) H T O
1 2 5
+ 2 7 3
____________
(ii) H T O
3 1 4
+ 4 4 5
____________
(iii) H T O
4 6 7
+ 2 0 0
____________
(iv) H T O
3 4 2
+ 2 3 7
____________
(v) H T O
6 5 3
+ 3 1 4
____________
(vi) H T O
4 1 2
+ 1 3 2
+ 2 0 1
____________
(vii) H T O
1 3
+ 3 3 2
+ 4 3 3
___________
(viii) H T O
3 3
+ 5 3 5
+ 1 1 0
___________
(ix) H T O
4
+ 4 2
+ 8 3 2
___________
(x) H T O
3 0 0
+ 1 7 0
+ 1 2 0
___________
(xi) H T O
5
+ 4 2
+ 3 1 0
+ 5 2 0
___________
(xii) H T O
3 6 0
+ 5
+ 2 1
+ 3 0 3
___________
(xiii) H T O
3 0 2
+ 4 1 2
+ 5 4
+ 2 3 1
___________
(xiv) H T O
4 1 3
+ 2 0 2
+ 1 4 2
+ 1 2 1
___________
(xv) H T O
1 1 1
+ 2 2 2
+ 2 1 2
+ 4 2 3
___________
Answer:
III. (i) 398
(ii) 759
(iii) 667
(iv) 579
(v) 967
(vi) 745
(vii) 778
(viii) 678
(ix) 878
(x) 590
(xi) 877
(xii) 689
(xiii) 999
(xiv) 878
(xv) 968
IV. Add the following 3-Digit Numbers Without Carrying:
|
(i) |
H T O 7 1 4 + 2 6 3 ____________ |
(ii) |
H T O 3 0 3 + 2 4 2 ____________ |
|
(iii) |
H T O 4 3 5 + 2 2 4 ____________ |
(iv) |
H T O 5 6 1 + 1 2 5 ____________ |
|
(v) |
H T O 1 5 2 + 5 2 6 ____________ |
(vi) |
H T O 8 6 0 + 1 2 4 ____________ |
|
(vii) |
H T O 1 1 1 + 6 2 5 ____________ |
(viii) |
H T O 2 1 3 + 3 2 4 ____________ |
|
(ix) |
H T O 7 9 1 + 2 0 8 ____________ |
(x) |
H T O 5 1 4 + 3 5 3 ____________ |
|
(xi) |
H T O 4 0 2 + 2 8 6 ____________ |
(xii) |
H T O 3 6 4 + 4 1 3 ____________ |
|
(xiii) |
H T O 7 0 9 + 2 7 0 ____________ |
(xiv) |
H T O 2 5 3 + 5 2 3 ____________ |
|
(xv) |
H T O 2 4 2 + 1 2 3 ____________ |
(xvi) |
H T O 3 1 2 + 5 6 5 ____________ |
1. What is addition without regrouping?
Answer:
Addition without regrouping means adding numbers without carrying any digit to the next place value.
2. How do you add 3-digit numbers without carrying?
Answer:
Arrange the numbers according to place value and add ones, tens, and hundreds separately.
3. What is the difference between regrouping and without regrouping?
Answer:
In regrouping, digits are carried over to the next place value. Without regrouping, no carrying is needed.
4. What grade learns 3-digit addition without regrouping?
Answer:
Usually Grade 2 and Grade 3 students learn this topic.
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