Subscribe to our YouTube channel for the latest videos, updates, and tips.


Long Division Method with Regrouping and without Remainder

We will discuss here how to solve step-by-step the long division method with regrouping and without remainder.

Consider the following examples:

A. Dividing a 2-Digits Number by 1-Digit Number With Regrouping and Without Remainder:

Dividing a 2-Digits Number by 1-Digit Number With Regrouping

Division by Regrouping 2-digit Numbers

1. Divide 92 by 4.

Solution:

Step I: Arrange the numbers in columns.

Divide 9 tens by 4.

4 × 2 = 8, 8 < 9

and 4 × 3 = 12, 12 > 9

So, 9 - 8 = 1

We have 1 ten left.


Step II:

Bring down 2 ones.

We now have 1 ten and 2 ones = 12 ones as the new dividend.

On reciting the table of 4,

we get 4 × 3 = 12

So, the quotient is 23.


B. Dividing a 3-Digits Number by 1-Digit Number With Regrouping and Without Remainder:

Division by Regrouping 3-digit Numbers

1. 468 ÷ 3

Let us follow the division along with the given steps.

Long Division Method with Regrouping and without Remainder

Step I: Begin with hundreds digit

4 hundreds ÷ 3 = 1 hundred with remainder 1 hundred

Step II: Bring down 6 tens to the right of 1 hundred

1 hundred + 6 tens = 16 tens

Step III: 16 tens ÷ 3 = 5 tens with remainder 1 ten

Step IV: Bring down 8 ones to the right of 1 ten

1 ten + 8 ones = 18 ones

Step V: 18 ones ÷ 3 = 6 ones

Therefore, 468 ÷ 3 = 156


2. Divide 675 by 3.

Solution: 

Dividing a 3-Digits Number by 1-Digit Number With Regrouping

Step I: Divide the 6 hundreds. (3 × 2 = 6)

Subtract the hundreds: 6 - 6 = 0

Step II: Divide the 7 tens. (3 × 2 = 6)

Subtract the tens: 7 - 6 = 1,

i.e., 1 ten is left.

So, bring down 5 ones.

Step III: Now, we have 10 ones (1 ten) + 5 ones = 15 ones.

Divide 15 ones by 3. (3 × 5 = 15)

Subtract the ones:

15 - 15 = 0

Therefore, Quotient = 225, Remainder = 0.


C. Dividing a 4-Digits Number by 1-Digit Number With Regrouping and Without Remainder:

1. 9120 ÷ 5

Let us follow the division along with the given steps.

Long Division with Regrouping and without Remainder

Step I: Begin with thousands digit

9 thousands ÷ 5 = 1 thousand with remainder 4 thousands

Step II: Bring down 1 hundred to the right of 4 thousands

Step III: Now 4 thousands + 1 hundred = 41 hundreds

Step IV: Now 41 hundreds ÷ 5 = 8 hundreds with remainder 1 hundred

Step V: Bring down 2 tens to the right of 1 hundred

Step VI: Now 1 hundred + 2 tens = 12 tens

Step VII: So, 12 tens ÷ 5 = 2 with remainder 2 tens

Step VIII: Bring down zero to the right of 2 tens

So, 2 tens + 0 ones = 20 ones

Now 20 ones ÷ 5 = 4 ones

Therefore, 9120 ÷ 5 = 1824





3rd Grade Math Worksheets

3rd Grade Math Lessons

From Long Division Method with Regrouping and without Remainder to HOME PAGE




Didn't find what you were looking for? Or want to know more information about Math Only Math. Use this Google Search to find what you need.



New! Comments

Have your say about what you just read! Leave me a comment in the box below. Ask a Question or Answer a Question.




Share this page: What’s this?

Recent Articles

RSS

  1. Worksheet on Average | Word Problem on Average | Questions on Average

    May 19, 25 02:53 PM

    Worksheet on Average
    In worksheet on average we will solve different types of questions on the concept of average, calculating the average of the given quantities and application of average in different problems.

    Read More

  2. 8 Times Table | Multiplication Table of 8 | Read Eight Times Table

    May 18, 25 04:33 PM

    Printable eight times table
    In 8 times table we will memorize the multiplication table. Printable multiplication table is also available for the homeschoolers. 8 × 0 = 0 8 × 1 = 8 8 × 2 = 16 8 × 3 = 24 8 × 4 = 32 8 × 5 = 40

    Read More

  3. How to Find the Average in Math? | What Does Average Mean? |Definition

    May 17, 25 04:04 PM

    Average 2
    Average means a number which is between the largest and the smallest number. Average can be calculated only for similar quantities and not for dissimilar quantities.

    Read More

  4. Problems Based on Average | Word Problems |Calculating Arithmetic Mean

    May 17, 25 03:47 PM

    Here we will learn to solve the three important types of word problems based on average. The questions are mainly based on average or mean, weighted average and average speed.

    Read More

  5. Rounding Decimals | How to Round a Decimal? | Rounding off Decimal

    May 16, 25 11:13 AM

    Round off to Nearest One
    Rounding decimals are frequently used in our daily life mainly for calculating the cost of the items. In mathematics rounding off decimal is a technique used to estimate or to find the approximate

    Read More