Long Division Method with Regrouping and without Remainder
We will discuss here how to solve step-by-step the long division method with regrouping and without remainder.
Consider the following examples:
A. Dividing a 2-Digits Number by 1-Digit Number With Regrouping and Without Remainder:
Division by Regrouping 2-digit Numbers
1. Divide 92 by 4.
Solution:
Step I: Arrange the numbers in columns.
Divide 9 tens by 4.
4 × 2 = 8, 8 < 9
and 4 × 3 = 12, 12 > 9
So, 9 - 8 = 1
We have 1 ten left.
Step II:
Bring down 2 ones.
We now have 1 ten and 2 ones = 12 ones as the new dividend.
On reciting the table of 4,
we get 4 × 3 = 12
So, the quotient is 23.
B. Dividing a 3-Digits Number by 1-Digit Number With Regrouping and Without Remainder:
Division by Regrouping 3-digit Numbers
1. 468 ÷ 3
Let us follow the division along with the given steps.
 |
Step I: Begin with hundreds digit 4 hundreds ÷ 3 = 1 hundred with remainder 1 hundred
Step II: Bring down 6 tens to the right of 1 hundred 1 hundred + 6 tens = 16 tens Step III: 16 tens ÷ 3 = 5 tens with remainder 1 ten Step IV: Bring down 8 ones to the right of 1 ten 1 ten + 8 ones = 18 ones Step V: 18 ones ÷ 3 = 6 ones |
Therefore, 468 ÷ 3 = 156
2. Divide 675 by 3.
Solution:
Step I: Divide the 6 hundreds. (3 × 2 = 6)
Subtract the hundreds: 6 - 6 = 0
Step II: Divide the 7 tens. (3 × 2 = 6)
Subtract the tens: 7 - 6 = 1,
i.e., 1 ten is left.
So, bring down 5 ones.
Step III: Now, we have 10 ones (1 ten) + 5 ones = 15 ones.
Divide 15 ones by 3. (3 × 5 = 15)
Subtract the ones:
15 - 15 = 0
Therefore, Quotient = 225, Remainder = 0.
C. Dividing a 4-Digits Number by 1-Digit Number With Regrouping and Without Remainder:
1. 9120 ÷ 5
Let us follow the division along with the given steps.
 |
Step I: Begin with thousands digit 9 thousands ÷ 5 = 1 thousand with remainder 4 thousands
Step II: Bring down 1 hundred to the right of 4 thousands Step III: Now 4 thousands + 1 hundred = 41 hundreds Step IV: Now 41 hundreds ÷ 5 = 8 hundreds with remainder 1 hundred Step V: Bring down 2 tens to the right of 1 hundred Step VI: Now 1 hundred + 2 tens = 12 tens Step VII: So, 12 tens ÷ 5 = 2 with remainder 2 tens Step VIII: Bring down zero to the right of 2 tens So, 2 tens + 0 ones = 20 ones Now 20 ones ÷ 5 = 4 ones |
Therefore, 9120 ÷ 5 = 1824
From Long Division Method with Regrouping and without Remainder to HOME PAGE
Didn't find what you were looking for? Or want to know more information about Math Only Math. Use this Google Search to find what you need.
Recent Articles
-
Converting Fractions to Decimals | Solved Examples | Free Worksheet
Apr 28, 25 01:43 AM
In converting fractions to decimals, we know that decimals are fractions with denominators 10, 100, 1000 etc. In order to convert other fractions into decimals, we follow the following steps: -
Expanded Form of a Number | Writing Numbers in Expanded Form | Values
Apr 27, 25 10:13 AM
We know that the number written as sum of the place-values of its digits is called the expanded form of a number. In expanded form of a number, the number is shown according to the place values of its… -
Converting Decimals to Fractions | Solved Examples | Free Worksheet
Apr 26, 25 04:56 PM
In converting decimals to fractions, we know that a decimal can always be converted into a fraction by using the following steps: Step I: Obtain the decimal. Step II: Remove the decimal points from th… -
Worksheet on Decimal Numbers | Decimals Number Concepts | Answers
Apr 26, 25 03:48 PM
Practice different types of math questions given in the worksheet on decimal numbers, these math problems will help the students to review decimals number concepts. -
Multiplication Table of 4 |Read and Write the Table of 4|4 Times Table
Apr 26, 25 01:00 PM
Repeated addition by 4’s means the multiplication table of 4. (i) When 5 candle-stands having four candles each. By repeated addition we can show 4 + 4 + 4 + 4 + 4 = 20 Then, four 5 times
New! Comments
Have your say about what you just read! Leave me a comment in the box below. Ask a Question or Answer a Question.