Addition of 3-Digit Numbers with Regrouping
We will learn addition of 3-digit numbers with regrouping.
1. Add 495 and 65.
Solution:
|
Step 1: Arrange the numbers vertically. Step 2: Add the ones. 5 + 5 = 10 ones = 1 ten and 0 one. Write 0 in the ones column and carry over 1 to the tens column. Step 3: Add the tens. 9 + 6 + 1 (carry over) = 16 tens = 1 hundred and 6 tens. Write 6 in the tens column and carry over 1 to the hundreds column. Step 4: Add the hundreds. 4 +1 (carry over) = 5 hundreds. Write 5 in the hundreds column. |
 Thus, 495 + 65 = 560 |
2. Add 379 and 558
Solution:
|
Step 1: Arrange the numbers vertically. Step 2: Add the ones column. 9 + 8 = 17 ones = 1 ten and 7 ones. Write 7 in the ones column and carry over 1 to the tens column. Step 3: Add the tens column. 7 + 5 + 1 (carry over) = 13 tens = 1 hundred and 3 tens. Write 3 in the tens column and carry over 1 to the hundreds column. Step 4: Add the hundreds column. 3 + 5 + 1 (carry over) = 9 hundreds. |
 Thus 379 + 558 = 937 |
Questions and Answers on Addition of 3-Digit Numbers with Regrouping:
I. Add the following numbers:
(i) 973 + 18
(ii) 536 + 69
(iii) 797 + 26
(iv) 479 + 32
(v) 284 + 33
(vi) 529 + 74
(vii) 664 + 9
(viii) 708 + 12
(ix) 675 + 38
(x) 468 + 68
(xi) 209 + 84
(xii) 900 + 92
(xiii) 421 + 79
(xiv) 579 + 78
(xv) 251 + 84
(xvi) 676 + 35
Answer:
I. (i) 981
(ii) 605
(iii) 826
(iv) 511
(v) 317
(vi) 603
(vii) 673
(viii) 740
(ix) 713
(x) 536
(xi) 393
(xii) 992
(xiii) 500
(xiv) 657
(xv) 335
(xvi) 711
II. Add the following numbers:
(i) 257 + 483
(ii) 559 + 207
(iii) 357 + 376
(iv) 436 + 354
(v) 618 + 162
(vi) 428 + 357
(vii) 364 + 546
(viii) 518 + 293
(ix) 329 + 600
(x) 533 + 428
(xi) 442 + 279
(xii) 269 + 542
(xiii) 364 + 263
(xiv) 490 + 240
(xv) 836 + 157
(xvi) 680 + 255
Answer:
II. (i) 740
(ii) 766
(iii) 733
(iv) 790
(v) 780
(vi) 785
(vii) 910
(viii) 811
(ix) 929
(x) 961
(xi) 721
(xii) 811
(xiii) 627
(xiv) 730
(xv) 993
(xvi) 935
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