Problems on coin toss probability are explained here with different examples.
When we flip a coin there is always a probability to get a head or a tail is 50 percent.
Suppose a coin tossed then we get two possible outcomes either a ‘head’ (H) or a ‘tail’ (T), and it is impossible to predict whether the result of a toss will be a ‘head’ or ‘tail’.
The probability for equally likely outcomes in an event is:
Number of favourable outcomes ÷ Total number of possible outcomes
Total number of possible outcomes = 2
(i) If the favourable outcome is head (H).
Number of favourable outcomes = 1.
Therefore, P(getting a head)
= 1/2.
(ii) If the favourable outcome is tail (T).
Number of favourable outcomes = 1.
Therefore, P(getting a tail)
Number of favorable outcomes= 1/2.
Word Problems on Coin Toss Probability:
1. A coin is tossed twice at random. What is the probability of getting
(i) at least one head
(ii) the same face?
Solution:
The possible outcomes are HH, HT, TH, TT.
So, total number of outcomes = 4.
(i) Number of favourable outcomes for event E
= Number of outcomes having at least one head
= 3 (as HH, HT, TH are having at least one head).
So, by definition, P(F) = \(\frac{3}{4}\).
(ii) Number of favourable outcomes for event E
= Number of outcomes having the same face
= 2 (as HH, TT are have the same face).
So, by definition, P(F) = \(\frac{2}{4}\) = \(\frac{1}{2}\).
2. If three fair coins are tossed randomly 175 times and it is found that three heads appeared 21 times, two heads appeared 56 times, one head appeared 63 times and zero head appeared 35 times.
What is the probability of getting
(i) three heads, (ii) two heads, (iii) one head, (iv) 0 head.
Solution:
Total number of trials = 175.
Number of times three heads appeared = 21.
Number of times two heads appeared = 56.
Number of times one head appeared = 63.
Number of times zero head appeared = 35.
Let E_{1}, E_{2}, E_{3} and E_{4} be the events of getting three heads, two heads, one head and zero head respectively.(i) P(getting three heads)
Number of times three heads appeared= 21/175
= 0.12
(ii) P(getting two heads)
Number of times two heads appeared= 56/175
=
0.32
(iii) P(getting one head)
Number of times one head appeared= 63/175
= 0.36
(iv) P(getting zero head)
Number of times zero head appeared= 35/175
= 0.20
Note: Remember when 3 coins are tossed randomly, the only possible outcomes
are E_{2}, E_{3}, E_{4} and= (0.12 + 0.32 + 0.36 + 0.20)
= 1
3. Two coins are tossed randomly 120 times and it is found that two tails appeared 60 times, one tail appeared 48 times and no tail appeared 12 times.
If two coins are tossed at random, what is the probability of getting
(i) 2 tails,
(ii) 1 tail,
(iii) 0 tail
Solution:
Total number of
trials = 120
Number of times 2 tails appear = 60
Number of times 1 tail appears
= 48
Number of times 0 tail appears
= 12
(i) P(getting 2 tails)
Number of times 2 tails appear= 60/120
= 0.50
(ii) P(getting 1 tail)
Number of times 1 tail appear= 48/120
= 0.40
(iii) P(getting 0 tail)
Number of times no tail appear= 12/120
= 0.10
Note:
Remember while tossing 2 coins simultaneously, the only possible outcomes are E_{1}, E_{2}, E_{3} and,= (0.50 + 0.40 + 0.10)
= 1
4. Suppose a fair coin is randomly
tossed for 75 times and it is found that head turns up 45
times and tail 30 times. What is the probability of getting (i)
a head and (ii) a tail?
Solution:
Total number of trials = 75.
Number of times head turns up = 45
Number of times tail turns up = 30
(i) Let X be the event of getting a head.
P(getting a head)
Number of times head turns up= 45/75
= 0.60
(ii) Let Y be the event of getting a tail.
P(getting a tail)
Number of times tail turns up
= 30/75
= 0.40
Note: Remember when a fair coin is tossed and then X and Y are the only possible outcomes, and
P(X) + P(Y)
= (0.60 + 0.40)
= 1Probability
Probability of Tossing Two Coins
Probability of Tossing Three Coins
Probability for Rolling Two Dice
Probability for Rolling Three Dice
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