Problems on Geometric Progression

Here we will learn how to solve different types of problems on Geometric Progression.

1. Find the common ratio of the Geometric Progression whose, sum of the third and fifth terms is 90 and its first term is 1.

Solution:

The first term of the given Geometric Progression a = 1.

Let ‘r’ be the common ratio of the Geometric Progression.

According to the problem,

 t_3 + t_5 = 90

ar^2 + ar^4 = 90

r^2 + r^4 = 90

r^4 + r^2 – 90 = 0

r^2 + 10r^2 - 9r^2 - 90 = 0

(r^2 + 10)(r^2 - 9) =0

r^2 - 9 = 0

r^2 = 9

r = ±3

Therefore, the common ratio of the Geometric Progression is -3 or 3.

2. Find a Geometric Progress for which the sum of first two terms is -4 and the fifth term is 4 times the third term.

Solution:

Let ‘a’ be the first term and ‘r’ be the common ratio of the given Geometric Progression.

Then, according to the problem the sum of first two terms is -4

t_1 + t_2 = -4

a + ar = -4 .................. (i)

and the fifth term is 4 times the third term.

t_5 = 4t_3

ar^4 = 4ar^2

r^2 = 4

r = ±2

Putting r = 2 and -2 respectively in (i), we get a = -4/3 and a = 4.

Thus, the required Geometric Progression is -4/3, -8/3, -16/3, ............ or 4, -8, 16, -32, ........................


3. Prove that in a Geometric Progression of finite number of terms the product of any two terms equidistant from the beginning and the end is constant and is equal to the product of the first and last and last terms.

Solution:

Let ‘a’ be the first term, ‘b’ the last term and ‘r’ the common ratio of a finite Geometric Progression.

Then the nth term from the beginning = a* r^(n - 1)

And the nth term from the end = b/r^(n -1)

Therefore, the product of two equidistant terms from the beginning and end (i.e., the terms at the nth positions) = a * r^(n - 1) * b/r^(n -1)  = a * b = constant = first term X last term.          Proved.

 Geometric Progression



11 and 12 Grade Math 

From Problems on Geometric Progression to HOME PAGE




Didn't find what you were looking for? Or want to know more information about Math Only Math. Use this Google Search to find what you need.



Share this page: What’s this?

Recent Articles

  1. Adding 1-Digit Number | Understand the Concept one Digit Number

    Apr 26, 24 01:55 PM

    Add by Counting Forward
    Understand the concept of adding 1-digit number with the help of objects as well as numbers.

    Read More

  2. Subtracting 2-Digit Numbers | How to Subtract Two Digit Numbers?

    Apr 26, 24 12:36 PM

    Subtracting 2-Digit Numbers
    In subtracting 2-digit numbers we will subtract or minus a two-digit number from another two-digit number. To find the difference between the two numbers we need to ‘ones from ones’ and ‘tens from

    Read More

  3. 1st Grade Word Problems on Subtraction | Subtracting 2-Digit Numbers

    Apr 26, 24 12:06 PM

    1st Grade Word Problems on Subtraction
    In 1st grade word problems on subtraction students can practice the questions on word problems based on subtraction. This exercise sheet on subtraction can be practiced by the students to get more ide…

    Read More

  4. Subtracting 1-Digit Number | Subtract or Minus Two One-Digit Number

    Apr 26, 24 11:21 AM

    Cross Out 6 Objects
    In subtracting 1-digit number we will subtract or minus one-digit number from one-digit number or one-digit number from 2-digit number and find the difference between them. We know that subtraction me…

    Read More

  5. Perimeter of a Square | How to Find the Perimeter of Square? |Examples

    Apr 25, 24 05:34 PM

    Perimeter of a Square
    We will discuss here how to find the perimeter of a square. Perimeter of a square is the total length (distance) of the boundary of a square. We know that all the sides of a square are equal. Perimete…

    Read More