Problems on Condition of Perpendicularity

Here we will solve various types of problems on condition of perpendicularity of two lines. 

1. Prove that the lines 5x + 4y = 9 and 4x – 5y – 1 = 0 are perpendicular to each other.

Solution:

Equation of the 1st line 5x + 4y = 9.

Now we need to express the above equation in the form y = mx + c.

5x + 4y = 9

4y = -5x + 9

y = -\(\frac{5}{4}\)x + \(\frac{9}{4}\)

Therefore, the slope (m \(_{1}\)) of the 1st line = -5/4

Equation of the second line 4x - 5y - 1 = 0

Now we need to express the above equation in the form y = mx + c.

4x – 5y – 1 = 0

⟹ -5y = -4x + 1

⟹ y = \(\frac{4}{5}\)– \(\frac{1}{5}\) 

Therefore, the slope (m \(_{2}\)) of the 2nd line = \(\frac{4}{5}\)

Now,

m \(_{1}\) × m \(_{2}\) = \(\frac{-5}{4}\)  ×  \(\frac{4}{5}\)= -1

Therefore, the given lines are perpendicular to each other.


2. Find the value of k if the lines 7y = kx + 4 and x + 2y = 3 are perpendicular.

Solution:

The slope of the lines can be found by comparing the equations with y = mx + c.

Equation of the first straight line 7y = kx + 4

Now we need to express the given equation in the form y = mx + c.

7y = kx + 4

⟹ y = \(\frac{k}{7}\)x + \(\frac{4}{7}\)

Therefore, the slope (m\(_{1}\)) of the given line = \(\frac{k}{7}\)

Equation of the second line x + 2y = 3

Now we need to express the given equation in the form y = mx + c.

x + 2y = 3

⟹ 2y = -x + 3

⟹ y = -\(\frac{1}{2}\)x + \(\frac{3}{2}\)

Therefore, the slope (m\(_{2}\)) of the given line = -\(\frac{1}{2}\)

Now according o the problem the two given lines are perpendicular.

i.e., m\(_{1}\) × m\(_{2}\) = -1

⟹ \(\frac{k}{7}\) × -\(\frac{1}{2}\) = -1

⟹ -\(\frac{k}{14}\) = -1

⟹ k = 14

Therefore, the value of k = 14

 Equation of a Straight Line










10th Grade Math

From Problems on Condition of Perpendicularity to HOME




Didn't find what you were looking for? Or want to know more information about Math Only Math. Use this Google Search to find what you need.



Share this page: What’s this?

Recent Articles

  1. Adding 1-Digit Number | Understand the Concept one Digit Number

    Apr 26, 24 01:55 PM

    Add by Counting Forward
    Understand the concept of adding 1-digit number with the help of objects as well as numbers.

    Read More

  2. Subtracting 2-Digit Numbers | How to Subtract Two Digit Numbers?

    Apr 26, 24 12:36 PM

    Subtracting 2-Digit Numbers
    In subtracting 2-digit numbers we will subtract or minus a two-digit number from another two-digit number. To find the difference between the two numbers we need to ‘ones from ones’ and ‘tens from

    Read More

  3. 1st Grade Word Problems on Subtraction | Subtracting 2-Digit Numbers

    Apr 26, 24 12:06 PM

    1st Grade Word Problems on Subtraction
    In 1st grade word problems on subtraction students can practice the questions on word problems based on subtraction. This exercise sheet on subtraction can be practiced by the students to get more ide…

    Read More

  4. Subtracting 1-Digit Number | Subtract or Minus Two One-Digit Number

    Apr 26, 24 11:21 AM

    Cross Out 6 Objects
    In subtracting 1-digit number we will subtract or minus one-digit number from one-digit number or one-digit number from 2-digit number and find the difference between them. We know that subtraction me…

    Read More

  5. Perimeter of a Square | How to Find the Perimeter of Square? |Examples

    Apr 25, 24 05:34 PM

    Perimeter of a Square
    We will discuss here how to find the perimeter of a square. Perimeter of a square is the total length (distance) of the boundary of a square. We know that all the sides of a square are equal. Perimete…

    Read More