Finding out the numbers possible with 1digit, 2digit, 3digit, etc,.
(a) The smallest 1digit number is 1.
The greatest 1digit number is 9.
Therefore, 9  1 = 8 and 8 + 1 = 9
So, we say that we have 9 onedigit numbers.
(b) The smallest 2digit number =10.
The greatest 2digit number = 99.
Therefore 99  10 = 89 and 89 + 1 = 90
So, we say that we have 90 twodigit numbers.
(c) The smallest 3digit number = 100.
The greatest 3digit number = 999.
There for 999  100 = 899 and 899 + 1 = 900
So, we say that we have 900 threedigit numbers.
(d) The smallest 4digit number = 1000.
The greatest 4digit number = 9999.
There for 9999  1000 = 8999 and 8999 + 1 = 9000
So, we say that we have 9000 fourdigit numbers.
We observe a pattern in this:
1digit number = 9
2digit numbers = 90
3digit numbers = 900
4digit numbers = 9000
Therefore, in finding out the numbers we can say 5digit numbers = 90000 and so on…..
Related Concept
● Numbers Showing on Spike Abacus.
● 1 Digit Number on Spike Abacus.
● 2 Digits Number on Spike Abacus.
● 3 Digits Number on Spike Abacus.
● 4 Digits Number on Spike Abacus.
● 5 Digits Number on Spike Abacus.
● Problems Related to Place Value.
● Example on Comparison of Numbers.
● Successor and Predecessor of a Whole Number.
● Formation of Numbers with the Given Digits.
● Formation of Greatest and Smallest Numbers.
● Examples on the Formation of Greatest and the Smallest Number.
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