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Vertex of the Ellipse

We will discuss about the vertex of the ellipse along with the examples.


Definition of the vertex of the ellipse:

The vertex is the point of intersection of the line perpendicular to the directrix which passes through the focus cuts the ellipse.

Suppose the equation of the ellipse be x2a2 + y2b2 = 1 then, from the above figure we observe that the line perpendicular to the directrix KZ and passing through the focus S cuts the ellipse at A and A'.

The points A and A', where the ellipse meets the line joining the foci S and S' are called the vertices of the ellipse.

Therefore, the ellipse has two vertices A and A' whose co-ordinates are (a, 0) and (- a, 0) respectively.

Solved examples to find the vertex of an ellipse:

1. Find the coordinates of the vertices of the ellipse 9x2 + 16y2 - 144 = 0.

Solution:

The given equation of the ellipse is 9x2 + 16y2 - 144 = 0

Now form the above equation we get,

9x2 + 16y2 = 144

Dividing both sides by 144, we get

x216 + y29 = 1

This is the form of x2a2 + y2b2 = 1, (a2 > b2), where a2 = 16 or a = 4 and b2 = 9 or b = 3

We know the coordinates of the vertices are (a, 0) and (-a, 0).

Therefore, the coordinates of the vertices of the ellipse 9x2 + 16y2 - 144 = 0 are (4, 0) and (-4, 0).

 

2. Find the coordinates of the vertices of the ellipse 9x2 + 25y2 - 225 = 0.

Solution:

The given equation of the ellipse is 9x2 + 25y2 - 225 = 0

Now form the above equation we get,

9x2 + 25y2 = 225

Dividing both sides by 225, we get

x225 + y29 = 1

Comparing the equation x225 + y29 = 1

with the standard equation of ellipse x2a2 + y2b2 = 1 (a2 > b2) we get,

a2 = 25 or a = 5 and b2 = 9 or b = 3

We know the coordinates of the vertices are (a, 0) and (-a, 0).

Therefore, the coordinates of the vertices of the ellipse 9x2 + 25y2 - 225 = 0 are (5, 0) and (-5, 0).

● The Ellipse





11 and 12 Grade Math 

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