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We will learn how to find the position of a point with respect to the ellipse.
The point P (x1, y1) lies outside, on or inside the ellipse x2a2 + y2b2 = 1 according as x21a2 + y21b2 – 1 > 0, = or < 0.
Let P (x1, y1) be any point on the plane of the ellipse x2a2 + y2b2 = 1 ………………….. (i)
From the point P (x1, y1) draw PM perpendicular to XX' (i.e., x-axis) and meet the ellipse at Q.
According to the above graph we see that the point Q and P have the same abscissa. Therefore, the co-ordinates of Q are (x1, y2).
Since the point Q (x1, y2) lies on the ellipse x2a2 + y2b2 = 1.
Therefore,
x21a2 + y22b2 = 1
y22b2 = 1 - x21a2 ………………….. (i)
Now, point P lies outside, on or inside the ellipse according as
PM >, = or < QM
i.e., according as y1 >, = or < y2
i.e., according as y21b2 >, = or < y22b2
i.e., according as y21b2 >, = or < 1 - x21a2, [Using (i)]
i.e., according as x21a2 + y21b2 >, = or < 1
i.e., according as x21a2 + y21b2 - 1 >, = or < 0
Therefore, the point
(i) P (x1, y1) lies outside the ellipse x2a2 + y2b2 = 1 if PM > QM
i.e., x21a2 + y21b2 - 1 > 0.
(ii) P (x1, y1) lies on the ellipse x2a2 + y2b2 = 1 if PM = QM
i.e., x21a2 + y21b2 - 1 = 0.
(ii) P (x1, y1) lies inside the ellipse x2a2 + y2b2 = 1 if PM < QM
i.e., x21a2 + y21b2 - 1 < 0.
Hence, the point P(x1, y1) lies outside, on or inside the ellipse x2a2 + y2b2 = 1 according as xx21a2 + y21b2 - 1 >, = or < 0.
Note:
Suppose E1 = x21a2 + y21b2 - 1, then the point P(x1, y1) lies outside, on or inside the ellipse x2a2 + y2b2 = 1 according as E1 >, = or < 0.
Solved examples to find the position of the point (x1, y1) with respect to an ellipse x2a2 + y2b2 = 1:
1. Determine the position of the point (2, - 3) with respect to the ellipse x29 + y225 = 1.
Solution:
We know that the point (x1, y1) lies outside, on or inside the ellipse
x2a2 + y2b2 = 1 according as
x21a2 + y21b2 – 1 > , = or < 0.
For the given problem we have,
x21a2 + y21b2 - 1 = 229 + (−3)225 – 1 = 49 + 925 - 1 = - 44225 < 0.
Therefore, the point (2, - 3) lies inside the ellipse x29 + y225 = 1.
2. Determine the position of the point (3, - 4) with respect to the ellipse x29 + y216 = 1.
Solution:
We know that the point (x1, y1) lies outside, on or inside the ellipse
x2a2 + y2b2 = 1 according as
x21a2 + y21b2 - 1 > , = or < 0.
For the given problem we have,
x21a2 + y21b2 - 1 = 329 + (−4)216 - 1 = 99 + 1616 - 1 = 1 + 1 - 1 = 1 > 0.
Therefore, the point (3, - 4) lies outside the ellipse x29 + y216 = 1.
● The Ellipse
11 and 12 Grade Math
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