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Position of a Point with respect to the Ellipse

We will learn how to find the position of a point with respect to the ellipse.

The point P (x1, y1) lies outside, on or inside the ellipse x2a2 + y2b2 = 1 according as x21a2 + y21b2 – 1 > 0, = or < 0.

Let P (x1, y1) be any point on the plane of the ellipse x2a2 + y2b2 = 1 ………………….. (i)

From the point P (x1, y1) draw PM perpendicular to XX' (i.e., x-axis) and meet the ellipse at Q.

According to the above graph we see that the point Q and P have the same abscissa. Therefore, the co-ordinates of Q are (x1, y2).

Since the point Q (x1, y2) lies on the ellipse x2a2 + y2b2 = 1.

Therefore,

x21a2 + y22b2 = 1        

y22b2 = 1 - x21a2 ………………….. (i)

Now, point P lies outside, on or inside the ellipse according as

PM >, = or < QM

i.e., according as y1 >, = or < y2

i.e., according as y21b2 >, = or < y22b2

i.e., according as y21b2 >, = or < 1 - x21a2, [Using (i)]

i.e., according as x21a2 + y21b2 >, = or < 1

i.e., according as x21a2 + y21b2 - 1 >, = or < 0

Therefore, the point

(i) P (x1, y1) lies outside the ellipse x2a2 + y2b2 = 1 if PM > QM

i.e., x21a2 + y21b2 - 1 > 0.

(ii) P (x1, y1) lies on the ellipse x2a2 + y2b2 = 1 if PM = QM

i.e., x21a2 + y21b2 - 1 = 0.

(ii) P (x1, y1) lies inside the ellipse x2a2 + y2b2 = 1 if PM < QM

i.e., x21a2 + y21b2 - 1 < 0.

Hence, the point P(x1, y1) lies outside, on or inside the ellipse x2a2 + y2b2 = 1 according as xx21a2 + y21b2  - 1 >, = or < 0.

Note:

Suppose E1 = x21a2 + y21b2 - 1, then the point P(x1, y1) lies outside, on or inside the ellipse x2a2 + y2b2 = 1 according as E1 >, = or < 0.

 

Solved examples to find the position of the point (x1, y1) with respect to an ellipse x2a2 + y2b2 = 1:

1. Determine the position of the point (2, - 3) with respect to the ellipse x29 + y225 = 1.  

Solution:

We know that the point (x1, y1) lies outside, on or inside the ellipse

x2a2 + y2b2 = 1 according as

x21a2 + y21b2 – 1 > , = or  < 0.

For the given problem we have,

x21a2 + y21b2 - 1 = 229 + (3)225 – 1 = 49 + 925 - 1 = - 44225 < 0.

Therefore, the point (2, - 3) lies inside the ellipse x29 + y225 = 1.


2. Determine the position of the point (3, - 4) with respect to the ellipse x29 + y216 = 1.  

Solution:

We know that the point (x1, y1) lies outside, on or inside the ellipse

x2a2 + y2b2 = 1 according as

x21a2 + y21b2 - 1 > , = or  < 0.

For the given problem we have,

x21a2 + y21b2 - 1 = 329 + (4)216 - 1 = 99 + 1616 - 1 = 1 + 1 - 1 = 1 > 0.

Therefore, the point (3, - 4) lies outside the ellipse x29 + y216 = 1.  

● The Ellipse






11 and 12 Grade Math 

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