We will learn in the simplest way how to find the parametric equations of a parabola.
The best and easiest form to represent the co-ordinates of any point on the parabola y\(^{2}\) = 4ax is (at\(^{2}\), 2at). Since, for all the values of ‘t’ the coordinates (at\(^{2}\), 2at) satisfy the equation of the parabola y\(^{2}\) = 4ax.
Together the equations x = at\(^{2}\) and y = 2at (where t is the parameter) are called the parametric equations of the parabola y\(^{2}\) = 4ax.
Let us discuss the parametric coordinates of a point and their parametric equations on the other standard forms of the parabola.
The following gives the parametric coordinates of a point on four standard forms of the parabola and their parametric equations.
Standard equation of the parabola y\(^{2}\) = -4ax:
Parametric coordinates of the parabola y\(^{2}\) = -4ax are (-at\(^{2}\), 2at).
Parametric equations of the parabola y\(^{2}\) = -4ax are x = -at\(^{2}\), y = 2at.
Standard equation of the parabola x\(^{2}\) = 4ay:
Parametric coordinates of the parabola x\(^{2}\) = 4ay are (2at, at\(^{2}\)).
Parametric equations of the parabola x\(^{2}\) = 4ay are x = 2at, y = at\(^{2}\).
Standard equation of the parabola x\(^{2}\) = -4ay:
Parametric coordinates of the parabola x\(^{2}\) = -4ay are (2at, -at\(^{2}\)).
Parametric equations of the parabola x\(^{2}\) = -4ay are x = 2at, y = -at\(^{2}\).
Standard equation of the parabola (y - k)\(^{2}\) = 4a(x - h):
The parametric equations of the parabola (y - k)\(^{2}\) = 4a(x - h) are x = h + at\(^{2}\) and y = k + 2at.
Solved examples to find the parametric equations of a parabola:
1. Write the parametric equations of the parabola y\(^{2}\) = 12x.
Solution:
The given equation y\(^{2}\) = 12x is of the form of y\(^{2}\) = 4ax. On comparing the equation y\(^{2}\) = 12x with the equation y\(^{2}\) = 4ax we get, 4a = 12 ⇒ a = 3.
Therefore, the parametric equations of the given parabola are x = 3t\(^{2}\) and y = 6t.
2. Write the parametric equations of the parabola x\(^{2}\) = 8y.
Solution:
The given equation x\(^{2}\) = 8y is of the form of x\(^{2}\) = 4ay. On comparing the equation x\(^{2}\) = 8y with the equation x\(^{2}\) = 4ay we get, 4a = 8 ⇒ a = 2.
Therefore, the parametric equations of the given parabola are x = 4t and y = 2t\(^{2}\).
3. Write the parametric equations of the parabola (y - 2)\(^{2}\) = 8(x - 2).
Solution:
The given equation (y - 2)\(^{2}\) = 8(x - 2) is of the form of (y - k)\(^{2}\) = 4a(x - h). On comparing the equation (y - 2)\(^{2}\) = 8(x - 2) with the equation (y - k)\(^{2}\) = 4a(x - h) we get, 4a = 8 ⇒ a = 2 , h = 2 and k = 2.
Therefore, the parametric equations of the given parabola are x = 2t\(^{2}\) + 2 and y = 4t + 2.
● The Parabola
11 and 12 Grade Math
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