# Parallelogram

In a parallelogram; opposite sides are equal, opposite angles are equal and diagonals bisect each other.

Prove that in a parallelogram:

(i) the opposite sides are equal;

(ii) the opposite angles are equal;

(iii) diagonals bisect each other.

Proof:

Let PQRS be a parallelogram. Draw its diagonal PR.

In ∆ PQR and ∆ RSP,

∠1 = ∠4       (alternate angles)

∠3 = ∠2       (alternate angles)

and PR = RP  (common)

Therefore, ∆ PQR ≅ ∆ RSP (by ASA congruence)

⇒ PQ = RS, QR = SP and ∠Q = ∠S.

Similarly, by drawing the diagonal QS, we can prove that

∆ PQS ≅ ∆ RSQ

Therefore, ∠P = ∠R

Thus, PQ = RS, QR = SP, ∠Q = ∠S and ∠P = ∠R.

This proves (i) and (ii)

In order to prove (iii) consider parallelogram PQRS and draw its diagonals PR and QS, intersecting each other at O.

In ∆ OPQand ∆ ORS, we have

PQ = RS                            [Opposite sides of a parallelogram]

∠POQ = ∠ ROS                   [Vertically opposite angles]

∠OPQ = ∠ORS                    [Alternate angles]

Therefore, ∆ OPQ ≅ ∆ ORS   [By ASA property]

⇒ OP = OR and OQ = OS.

This shows that the diagonals of a parallelogram bisect each other.

The converse of the above result is also true, i.e.,

(i) If the opposite sides of a quadrilateral are equal then it is a parallelogram.

(i) If the opposite angles of a quadrilateral are equal then it is a parallelogram.

(i) If the diagonals of a quadrilateral bisect each other then it is a parallelogram.

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