Here we will learn about the graph of area vs. side of a square.

We know that area of a square = (side)(a) Consider the relation between the area and the side of a square, given by A = x

Draw a graph of the above function.

(b) From the graph, find the value of A, when x = 4.

The given function is A = x

For different values of x, we get the corresponding value of A.

x= 0 ⇒ A = 0

x= 1 ⇒ A = 1

x = 2 ⇒ A = 2

x = 3 ⇒ A = 3

x |
0 | 1 | 2 | 3 |
---|---|---|---|---|

^{2} |

Thus, we have the
points O (0, 0), B (1, 1), C (2, 4) and D (3, 9).

Plot these points on a graph paper and join them
successively to obtain the required graph given below.

**2. Reading off from the graph**** ****of area vs. side of a square:**

On the x-axis, take the point L at x = 4.

Draw LP ⊥ x-axis, meeting the given graph at P.

Clearly, PL = 16 units.

Therefore, x = 4 ⇒ A = 16.

Thus, when x = 4 units, then A = 16 sq. units

**Related Concepts:**

**● Ordered pair of a Coordinate System**

**● Find the Coordinates of a Point**

**● Coordinates of a Point in a Plane**

**● Plot Points on Co-ordinate Graph**

**● Simultaneous Equations Graphically**

**● Graph of Perimeter vs. Length of the Side of a Square**

**● Graph of Simple Interest vs. Number of Years
**

**7th Grade Math Problems**

**8th Grade Math Practice**

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