Divisible by 7 is discussed below:

We need to double the last digit of the number and then subtract it from the remaining number. If the result is divisible by 7, then the original number will also be divisible by 7.

Consider the following numbers which are divisible by 7, using the test of divisibility by 7: 133, 273, 329, 595, 672.**(i) 133**

In the number 133, double the last digit of the number 3 is 6. 13 – 6 = 7 [Now we need to subtract it from the rest of the remaining number]

Since 7 is divisible by 7.

Hence, 133 is also divisible by 7.

**(ii) 273**

In the number 273, double the last digit of the number 3 is 6. 27 – 6 = 21 [Now we need to subtract it from the rest of theremaining number]

Since 21 is divisible by 7.

Hence, 273 is also divisible by 7.

**(iii) 329**

In the number 329, double the last digit of the number9 is 18. 32 – 18 = 14 [Now we need to subtract it from therest of theremaining number]

Since 14 is divisible by 7.

Hence, 329is also divisible by 7.

**(iv) 595**

In the number 595, double the last digit of the number5 is 10. 59 – 10 = 49 [Now we need to subtract it from therest of theremaining number]

Since 49 is divisible by 7.

Hence, 595is also divisible by 7.

**(v) 672**

In the number 672, double the last digit of the number2 is 4. 67 – 4 = 63 [Now we need to subtract it from therest of theremaining number]

Since 63 is divisible by 7.

Hence, 672is also divisible by 7.

Consider the following numbers which are not divisible by 7, using the rules of divisibility by 7: 167, 233, 297, 305,317.**(i) 167**

In the number 167, double the last digit of the number 7 is 14. 16 – 14 = 2 [Now we need to subtract it from therest of theremaining number]

Since 2 is not divisible by 7.

Hence, 167 is also not divisible by 7.

**(ii) 233**

In the number 233, double the last digit of the number 3 is 6. 23 – 6 = 17 [Now we need to subtract it from therest of theremaining number]

Since 17 is not divisible by 7.

Hence, 233 is also not divisible by 7.

**(iii)297**

In the number 297, double the last digit of the number 7 is 14. 29 – 14 = 15 [Now we need to subtract it from therest of theremaining number]

Since 15 is not divisible by 7.

Hence, 297 is also not divisible by 7.

**(iv) 305**

In the number 305, double the last digit of the number 5 is 10. 30 – 10 = 20 [Now we need to subtract it from therest of theremaining number]

Since 20 is not divisible by 7.

Hence, 305 is also not divisible by 7.

**(v) 317**

In the number 317, double the last digit of the number 7 is 14. 31 – 14 = 17 [Now we need to subtract it from therest of theremaining number]

Since 17 is not divisible by 7.

Hence, 317is also not divisible by 7.

**Problems on Divisibility Rules**

**Worksheet on Divisibility Rules**

**5th Grade Math Problems ****From Divisible by 7 to HOME PAGE**

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