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Arranging Ratios

We will learn how to solve different types of problems on arranging ratios in ascending order and descending order.

When a ratio is expressed in fraction or in decimal we first need to convert the ratio into whole number to compare the ratios.

The order of a ratio is important to compare two or more ratios. By reversing the antecedent and consequent of a ratio are different ratio is obtained.


Solved problems on comparing and arranging ratios in ascending and descending order:

1. Compare the ratios 113 : 115 and 1.6 : 1.2

Solution:

113 : 115 and 1.6 : 1.2

= 43 : 65 and 1610 : 1210

= 43 × 15 : 65 × 15 and 1610 × 10 : 1210 × 10

= 20 : 18 and 16 : 12

= 2018 and 1612

= 10×29×2 and 4×43×4

= 109 and 43

= 10 : 9 and 4 : 3

Now, 109 and 43 are to be compared. L.C.M. of 9 and 3 = 9

109 = 10×19×1 and 43 = 4×33×3

= 109 and 129

Since, 109 < 129

Therefore, 10 : 9 < 4 : 3

Hence, 113 : 115 < 1.6 : 1.2


2. Compare the ratios 14 : 23, 5 : 12 and 61 : 92 in ascending order.

Solution:

Given ratios can be written as 1423, 512 and 6192

L.C.M. of the denominators 23, 12 and 92 = 276

1423 = 14×1223×12 = 168276

512 = 5×2312×23 = 115276

and

6192 = 61×392×3 = 183276

Since, 115276 < 168276 < 183276

Therefore, 512 < 1423 < 6192

Hence, 5 : 12 < 14 : 23 < 61 : 92



3. Arrange the ratios 1 : 3, 5 : 12, 4 : 15 and 2 : 3 in descending order.

Solution:

Given ratios can be written as 13, 512, 415 and 23

L.C.M. of the denominators 3, 12, 15 and 3 = 60

13 = 1×203×20 = 2060

512 = 5×512×5 = 2560

415 = 4×415×4 = 1660

and

23 = 2×203×20 = 4060

Since, 4060 > 2560 > 2060 > 1660

Therefore, 23 > 512 > 13 > 415

Hence, 2 : 3 > 5 : 12 > 1 : 3 >  4 : 15.


● Ratio and proportion









10th Grade Math

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