Sum of angles of a quadrilateral are discussed here. We have now two triangles in the below figure.

We know, *the sum of the angles of a triangle = 180°*

Since there are two triangles,

therefore, the sum of two triangles is 180° + 180° = 360°

**Note:** The sum of the four angles is 360°.

**For Example:**

**1.** In a quadrilateral ABCD, ∠A = 100°, ∠B = 105° and ∠C = 70°, find ∠D.

**Solution:**

Here the sum of the four angles

or, ∠A + ∠B + ∠C + ∠D = 360°

We know, ∠A = 100°, ∠B = 105° and ∠C = 70°

or, 100° + 105° + 70° + ∠D = 360°

or, 275° + ∠D = 360°

∠D = 360° - 275°

Therefore, ∠D = 85°

**2.** Find the measure of the missing angles in a parallelogram, if ∠A = 70°.

**Solution:**

We know the opposite angles of a parallelogram are equal.

So, ∠C will also measure 70°

Sum of angles = 360°

∠A + ∠B + ∠C + ∠D = 360°

or, 70° + ∠B + 70° + ∠D = 360° (We know, ∠A = ∠C )

or, ∠B + ∠D + 140° = 360°

or, ∠B + ∠D = 360° - 140°

or, ∠B + ∠D = 220°

But ∠B = ∠D (Because opposites angles of a parallelogram are equal)

∠B = ∠D

= 220° ÷ 2

= 110°

Therefore, ∠B = 110°, ∠C = 70° and ∠ D = 110°

**Construction of Perpendicular Lines by using a Protractor.**

**Sum of Angles of a Quadrilateral.**

**Practice Test on Quadrilaterals.**

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