Situations of Direct Variation
We will learn ‘what direct variation is’ and how to solve different types of problems on some situations of direct variation.
If two quantities are related in such a way that the increase in one quantity results in a corresponding increase in the other and vice versa, then such a variation is called a direct variation.
If the two quantities are in direct variation then we also say that they are proportional to each other.
Suppose, if the two quantities ‘x’ and ‘y’ are in direct variation, then the ratio of any two values of x is equal to the ratio of the corresponding values of y.
i.e., \(\frac{x_{1}}{x_{2}} = \frac{y_{1}}{y_{2}}\)
or, \(\frac{x_{1}}{y_{1}} = \frac{x_{2}}{y_{2}}\)
Some situations of direct variation:
● More articles, more money required to purchase
Less articles, less money required to purchase.
● More men at work, more work is done..
Less men at work, less work is done.
● More money borrowed, more interest is to be paid.
Less money borrowed, less interest to be paid.
● More speed, more distance covered in fixed time.
Less speed, less distance covered in fixed time.
● More working hours, more work will be done.
Less working hours, less work will be done.
Problems on different
situations of direct variation:
1. If 12 flowerpots cost $156, what do 28 flowerpots cost?
Solution:
This is the situation of direct variation as
More flowerpots, result in more cost.
Cost of 12 flowerpots = $ 156
Cost of 1 flowerpot = $ (156/12)
Cost of 28 flowerpots = $ (156/12 × 28) = $ 364
2. A motor bike travels 280 km in 40 liters of petrol. How much distance will it cover in 9 liters of petrol?
Solution:
This is the situation of direct variation.
Less quantity of petrol, less distance covered.
In 40 liters of petrol, distance covered = 280 km
In 1 liter of petrol, distance covered = 280/40 km
In 9 liters of petrol, distance covered = 280/40 × 9 km = 63 km
Situations of Direct Variation
Situations of Inverse Variation
Direct Variations Using Unitary Method
Direct Variations Using Method of Proportion
Inverse Variation Using Unitary Method
Inverse Variation Using Method of Proportion
Problems on Unitary Method using Direct Variation
Problems on Unitary Method Using Inverse Variation
Mixed Problems Using Unitary Method
7th Grade Math Problems
From Situations of Direct Variation to HOME PAGE
Didn't find what you were looking for? Or want to know more information about Math Only Math. Use this Google Search to find what you need.
Recent Articles
-
Worksheet on Mixed Addition and Subtraction | Questions on Addition
Jan 12, 25 02:14 PM
In worksheet on mixed addition and subtraction the questions involve both addition and subtraction together; all grade students can practice the questions on addition and subtraction together. -
Estimating Sums and Differences | Estimations | Practical Calculations
Jan 12, 25 02:02 PM
For estimating sums and differences in the number we use the rounded numbers for estimations to its nearest tens, hundred, and thousand. In many practical calculations, only an approximation is requir… -
Combination of Addition and Subtraction | Mixed Addition & Subtraction
Jan 12, 25 01:36 PM
We will discuss here about the combination of addition and subtraction. The rules which can be used to solve the sums involving addition (+) and subtraction (-) together are: I: First add -
Checking Subtraction using Addition |Use Addition to Check Subtraction
Jan 12, 25 01:13 PM
We can check subtraction by adding the difference to the smaller number. Since the sum of difference and smaller number is equal to the larger number, subtraction is correct. -
Worksheet on Subtraction of 4-Digit Numbers|Subtracting 4-Digit Number
Jan 12, 25 09:04 AM
Practice the questions given in the worksheet on subtraction of 4-digit numbers. Here we will subtract two 4-digit numbers (without borrowing and with borrowing) to find the difference between them.
Worksheet on Direct Variation using Unitary Method
Worksheet on Direct variation using Method of Proportion
Worksheet on Word Problems on Unitary Method
New! Comments
Have your say about what you just read! Leave me a comment in the box below. Ask a Question or Answer a Question.