Simple Math Formula on Trigonometry

Simple math formula on trigonometry is given in such an order that students can easily get the formula.


Trigonometry

● Measurement of Trigonometrical Angles:

(i) The angle subtended at the centre of a circle by an arc whose length is equal to the radius of the circle is called a radian.

(ii) A radian is a constant angle. 

One radian = (2/π) rt. angle = 57°17’44.8” (approx.) 

(iii) 1 rt. angle = 90° ; 1° = 60’ ; 1‘ = 60”. 

(iv) 1 rt. angle = 100ᵍ ; 1ᵍ = 100’ ; 1‵ = 100‶.

(v) πᶜ 180° = 200ᵍ.

(vi) The circumference of a circle of radius r is 2πr where π is a constant; approximate value of π is ²²/₇; more accurate value of π is 3.14159 (approx.).

(vii) If Θ be the radian measure of an angle subtended at the centre of a circle of radius r by an arc of length s then Θ = ˢ/₀ or, s = rΘ.


● Trigonometrical Ratios of some Standard Angles:

Trigonometrical Ratios of some Standard Angles

● Trigonometrical Ratios for Associated Angles:

Trigonometrical Ratios for Associated Angles

(ii) If Θ is a positive acute angle and n is an even integer then,

(a) sin (n ∙ 90° ± Θ) = sin Θ or, (- sin Θ)

(b) cos (n ∙ 90° ± Θ) = cos Θ or, (- cos Θ)

(c) tan (n ∙ 90° ± Θ) = tan Θ or, (- tan Θ).

(iii) If Θ is a positive acute angle and n is an odd integer then,

(a) sin (n ∙ 90° ± Θ) = cos Θ or, (- cos Θ)

(b) cos (n ∙ 90° ± Θ) = sin Θ or, (- sin Θ)

(c) tan (n ∙ 90° ± Θ) = cot ф or (- cot Θ).



● Compound Angles:

(i) sin (A + B) = sin A cos B + cos A sin B.

(ii) sin ( A - B) = sin A cos B - cos A sin B.

(iii) cos (A + B) = cos A cos B + sin A sin B.

(iv) cos (A - B) = cos A cos B + sin A sin B.

(v) sin (A + B) sin (A - B) = sin² A - sin² B = cos² B - cos² A.

(vi) cos (A + B) cos (A - B) = cos² A - sin² B = cos² B - sin² A.

(vii) tan (A+ B) = (tan A + tan B)/(1 - tan A tan B).

(viii) tan (A - B) = (tan A - tan B)/(1 + tan A tan B).

(ix) cot (A + B) = (cot A cot B - 1)/(cot B + cot A).

(x) cot (A - B) = (cot A cot B + 1)/(cot B - cot A).

(xi) tan (A + B + C) = {(tan A + tan B + tan C) - (tan A tan B tan C)}/(1 - tan A tan B - tan B tan C - tan C tan A).

(xii) 2 sin A cos B = sin (A + B) + sin(A - B).

(xiii) 2 cos A sin B = sin (A + B ) - sin (A - B).

(xiv) 2 cos A cos B = cos (A + B ) + cos (A - B).

(xv) 2 sin A sin B = cos (A - B) - cos (A + B).

(xvi) sin C + sin D = 2 sin (C + D)/2 cos (C - D)/2.

(xvii) sin C - sin D = 2 cos (C + D)/2 sin (C - D)/2.

(xviii) cos C + cos D = 2 cos (C + D)/2 cos (C - D)/2.

(xix) cos C - cos D = 2 sin (C + D)/2 sin (C - D)/2.

● Multiple Angles:

(i) sin 2Θ = 2 sin Θ cos Θ.

(ii) cos 2Θ = cos² Θ - sin² Θ.

(iii) cos 2 Θ = 2 cos² Θ - 1.

(iv) cos 2Θ = 1 - 2 sin² Θ.

(v) 1 - cos2Θ = 2 cos² Θ.

(vi) 1 - cos2Θ = 2 sin² Θ.

(vii) tan² Θ = (1 - cos 2Θ)/(1 + cos 2Θ).

(viii) sin 2Θ = (2 tan Θ)/(1 + tan² Θ)

(ix) cos 2Θ = (1 - tan² Θ)/(1 + tan² Θ).

(x) tan 2Θ = (2 tan Θ)/(1 - tan² Θ).

(xi) sin 3Θ = 3 sin Θ - 4 sin³ Θ.

(xii) cos 3ф = 4 cos³ Θ - 3 cos Θ.

(xiii) tan 3Θ = (3 tan Θ - tan³ Θ)/(1 - 3 tan² Θ).

● Submultiple Angles:

(i) sin Θ = 2 sin (Θ/2) cos (Θ/2).

(ii) cos Θ = cos² (Θ/2) - sin² (Θ/2).

(iii) cos Θ = 2 cos² (Θ/2) - 1.

(iv) cos ф = 1 - 2 sin² (Θ/2).

(v) 1 + cos Θ = 2 cos² (Θ/2).

(vi) 1 - cos Θ = 2 sin² (Θ/2).

(vii) tan² (Θ/2) = (1 - cos Θ)/(1 + cos Θ).

(viii) sin Θ = [2 tan (Θ/2)]/[1 + tan² (Θ/2)].

(ix) cos Θ = [1 - tan² (Θ/2)]/[1 + tan² (Θ/2)].

(x) tan Θ = [2 tan (Θ/2)]/[1 - tan² (Θ/2)].

(xi) sin Θ = 3 sin (Θ/3) - 4 sin³ (Θ/3).

(xii) cos Θ = 4 cos³ (Θ/3) - 3 cos (Θ/2).

(xiii) (a) sin 15° = cos 75° = (√3 - 1)/(2√2).

(b) cos 15° = sin 75° = (√3 + 1)/(2√2).

(c) tan 15° = 2 - √3.

(d) sin 22 ½° = √(2 - √2).

(e) cos 22 ½° = ½ [√(2 + √2)].

(f) tan 22 ½° = √2 - 1.

(g) sin 18 ° = (√5 - 1)/4 = cos 72°.

(h) cos 36° = cos 72° = (√5 + 1)/4.

(i) cos 18° = sin 72° = ¼ [√(10 + 2√5)].

(j) sin 36° = cos 54° = ¼ [√(10 - 2√5)].



● General Solutions:

(i) (a) If sin Θ = 0 then, Θ = nπ.

(b) If sin Θ = 1 then, Θ = (4n + 1)(π/2).

(c) If sin ф = -1 then, Θ = (4n - 1)(π/2).

(d) If sin Θ = sin α then, Θ = nπ + (-1)ⁿ α.

(ii) (a) If cos Θ = 0 then, Θ = (2n + 1)(π/2).

(b) If cos Θ = 1 then, Θ = 2nπ.

(c) If cos Θ = -1 then, Θ = (2n + 1)π.

(d) If cos Θ = cos α then, Θ = 2nπ ± α.

(ii) (a) If tan Θ = 0 then, Θ = nπ.

(b) If tan Θ = tan α then, Θ = 2nπ + α where, n = 0 or any integer.



● Inverse Circular Functions:

(i) sin (sin-1 x) = x ; cos (cos-1 x) = x ; tan (tan-1 x) = x.

(ii) sin-1 (sin Θ) = Θ ; cos-1 (cos Θ) = Θ ; tan-1 (tan Θ) = Θ.

(iii) sin-1 x = cosec-1 (1/x) = cos-1 [√(1 - x2)] = sec-1 [1/√(1 - x2)]

= tan-1 [x/√(1 - x2)] = cot-1 [√(1 - x2)/x].

(iv) sin-1 x + cos-1 x = π/2 ; sec-1 x + cosec-1 x = π/2 ;

tan-1 x + cot-1 x = π/2.

(v) (a) tan-1 x + tan-1 y = tan-1 [(x + y)/(1 - xy)]

(b) tan-1 x - tan-1 y = tan-1 [(x - y)/(1 + xy)]

(vi) (a) sin-1 x + sin-1 y = sin-1 {x√(1 - y2) + y√(1 - x2)}

(b) sin-1 x - sin-1 y = sin-1 {x√(1 - y2 ) - y√(1 - x2)}

(vii) (a) cos-1 x + cos-1 y = cos-1 {xy - √(1 - x2) (1 - y2)}

(b) cos-1 x - cos-1 y = cos-1 {xy + √(1 - x2) (1 - y2)}.

(viii) 2 tan-1 x = sin-1 [2x/(1 + x2)] = cos-1 [(1 - x2)/(1 - x2)]

= tan-1 [2x/(1 - x2)].

(ix) tan-1 x + tan-1 y + tan-1 z = tan-1 [(x + y + z - xyz)/(1 - xy - yz - zx)]

(x) sin-1 x and cos-1 x are defined when -1 ≤ x ≤ 1 ; sec-1 x and cosec-1 x are defined when Ι x Ι ≥ 1 ; tan-1 x and cot-1 x are defined
when - ∞ < x < ∞.

(xi) If principal values of sin-1 x, cos-1 x and tan-1 x be α, β and γ respectively, then -π/2 ≤ α ≤ π/2, 0 ≤ β ≤ π and -π/2 ≤ γ ≤ π/2.

● Properties of Triangle:

(i) a/(sin A) = b/(sin B) = c/(sin C) = 2R.

(ii) a = b cos C + c cos B ; b = c cos A + a cos C ; c = a cos B + b cos A.

(iii) cos A = (b² + c² - a²)/2bc ; cos B = (c² + a² - b²)/2ca ;

cos C = (a² + b² - c²)/2ab

(iv) tan A = [(abc)/R] ∙[ 1/(b² + c² - a²)]

tan B = [(abc)/R] ∙ [1/(c² + a² - b²)]

tan C = [(abc)/R] ∙ [1/(a² + b² - c²)].

(v) sin (A/2) = √[(s - b) (s - c)/(bc)].

sin B/2 = √[(s - c) (s - a)/(ca)].

sin C/2 = √[(s - a) (s - b)/(ab)].

cos A/2 = √[s (s - a)/(bc)].

sin B/2 = √[s (s - b)/(ca)].

cos C/2 = √[s (s - c)/(ab)].

tan A/2 = √[(s - b) (s - c)/{s(s - c)}].

tan B/2 = √[(s - c) (s - a)/{s(s - b)}].

tan C/2 = √[(s - a) (s - b)/{s(s - c)}].

(vi) tan [(B - C)/2] = [(b - c)/(b + c)] cot (A/2).

tan [(C - A)/2] = [(c - a)/(c + a)] cot (B/2).

tan [(A - B)/2] = [(a - b)/(a + b)] cot (C/2).

(vii) ∆ = ½ [bc sin A] = ½ [ca sin B] = ½ [ab sin C].

(viii) ∆ = √{s(s - a)(s - b)(s - c)}.

(ix) R = ᵃᵇᶜ/₄₀.

(x) tan (A/2) = {(s - b)(s - c)}/∆.

tan (B/2) = {(s - c)(s - a)}/∆.

tan (C/2) = {(s - a)(s - b)}/∆

(xi) cot A/2 = {s(s - a)}/∆.

cot (B/2) = {s(s - b)}/∆.

cot (C/2) = {s(s - c)}/∆.

(xii) sin A = 2∆/bc ; sin B = 2∆/ca ; sin C = 2∆/ab

(xiii) r = ∆/s.

(xiv) r = 4R sin (A/2) sin (B/2) sin (C/2).

(xv) r = (s - a) tan (A/2) = (s - b) tan (B/2) = (s - c) tan (C/2).

(xvi) r₁ = ∆/(s - a) ; r₂ = ∆/(s - b); r₃ = ∆/(s - c) .

(xvii) r₁ = 4 R sin (A/2) cos (B/2) cos (C/2).

(xviii) r₂ = 4R sin (B/2) cos (C/2) cos (A/2).

(xix) r₃ = 4 R sin (C/2) cos (A/2) cos (B/2).

(xx) r₁ = s tan (A/2) ; r₂ = s tan (B/2) ; r₃ = s tan (C/2).

Formula




11 and 12 Grade Math

From Simple Math Formula on Trigonometry to HOME PAGE


New! Comments

Have your say about what you just read! Leave me a comment in the box below. Ask a Question or Answer a Question.

Recent Articles

  1. Adding 1-Digit Number | Understand the Concept one Digit Number

    Sep 17, 24 02:25 AM

    Add by Counting Forward
    Understand the concept of adding 1-digit number with the help of objects as well as numbers.

    Read More

  2. Counting Before, After and Between Numbers up to 10 | Number Counting

    Sep 17, 24 01:47 AM

    Before After Between
    Counting before, after and between numbers up to 10 improves the child’s counting skills.

    Read More

  3. Worksheet on Three-digit Numbers | Write the Missing Numbers | Pattern

    Sep 17, 24 12:10 AM

    Reading 3-digit Numbers
    Practice the questions given in worksheet on three-digit numbers. The questions are based on writing the missing number in the correct order, patterns, 3-digit number in words, number names in figures…

    Read More

  4. Arranging Numbers | Ascending Order | Descending Order |Compare Digits

    Sep 16, 24 11:24 PM

    Arranging Numbers
    We know, while arranging numbers from the smallest number to the largest number, then the numbers are arranged in ascending order. Vice-versa while arranging numbers from the largest number to the sma…

    Read More

  5. Worksheet on Tens and Ones | Math Place Value |Tens and Ones Questions

    Sep 16, 24 02:40 PM

    Tens and Ones
    In math place value the worksheet on tens and ones questions are given below so that students can do enough practice which will help the kids to learn further numbers.

    Read More