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Multiplication of Algebraic Expression
Thus, (x3 × x5) = x8, (x6 + x4) = x(6 + 4) = x10, etc. I. Multiplication of Two MonomialsRule:Product of two monomials = (product of their numerical coefficients) × (product of their variable parts) Find the product of:(i) 6xy and -3x2y3Solution:(6xy) × (-3x2y3) = {6 × (-3)} × {xy × x2y3} = -18x1 + 2 y1 + 3 = -18x3y4. (ii) 7ab2, -4a2b and -5abcSolution:(7ab2) × (-4a2b) × (-5abc) = {7 × (-4) × (-5)} × {ab2 × a2b × abc} = 140 a1 + 2 + 1 b2 + 1 + 1 c = 140a4b4c. II. Multiplication of a Polynomial by a MonomialRule:Multiply each term of the polynomial by the monomial, using the distributive law a × (b + c) = a × b + a × c. Find each of the following products:(i) 5a2b2 × (3a2 - 4ab + 6b2)Solution:5a2b2 × (3a2 - 4ab + 6b2) = (5a2b2) × (3a2) + (5a2b2) × (-4ab) + (5a2b2) × (6b2) = 15a4b2 - 20a3b3 + 30a2b4. (ii) (-3x2y) × (4x2y - 3xy2 + 4x - 5y)Solution:(-3x2y) × (4x2y - 3xy2 + 4x - 5y) = (-3x2y) × (4x2y) + (-3x2y) × (-3xy2) + (-3x2y) × (4x) + (-3x2y) × (-5y) = -12x4y2 + 9x3y3 - 12x3y + 15x2y2.
This method is known as the horizontal method.(i) Multiply (3x + 5y) and (5x - 7y).Solution:(3x + 5y) × (5x - 7y) = 3x × (5x - 7y) + 5y × (5x - 7y) = (3x × 5x - 3x × 7y) + (5y × 5x - 5y × 7y) = (15x2 - 21xy) + (25xy - 35y2) = 15x2 - 21xy + 25xy - 35y2 = 15x2 + 4xy - 35y2. Column wise multiplicationThe multiplication can be performed column wise as shown below.3x + 5y × (5x - 7y) _____________ 15x2 + 25xy ⇐ multiplication by 5x. - 21xy - 35y2 ⇐ multiplication by -7y. (ii) Multiply (3x2 + y2) by (2x2 + 3y2)Solution:Horizontal method,= 3x2 (2x2 + 3y2) + y2 (2x2 + 3y2)= (6x4 + 9x2y2) + (2x2y2 + 3y4) = 6x4 + 9x2y2 + 2x2y2 + 3y4 = 6x4 + 11x2y2 + 3y4 Column methods, 3x2 + y2
(i) Multiply (5x2 – 6x + 9) by (2x -3) 5x2 – 6x + 9 (ii) Multiply (2x2 – 5x + 4) by (x2 + 7x – 8)Solution:By column method 2x2 – 5x + 4 × (x2 + 7x – 8) ___________________________ 2x4 – 5x3 + 4x2 ⇐ multiplication by x2. + 14x3 - 35x2 + 28x ⇐ multiplication by 7x. - 16x2 + 40x - 32 ⇐ multiplication by -8. ___________________________ 2x4 – 9x3 - 47x2 + 68x - 32 ⇐ multiplication by (x2 + 7x - 8). ___________________________ Therefore, (2x2 – 5x + 4) by (x2 + 7x – 8) is 2x4 – 9x3 - 47x2 + 68x – 32. (iii) Multiply (2x3 – 5x2 – x + 7) by (3 - 2x + 4x2)Solution:Arranging the terms of the given polynomials in descending power of x and then multiplying, 2x3 – 5x2 – x + 7 × (3 - 2x + 4x2) _________________________________ 8x5 - 20x4 – 4x3 + 28x2 ⇐ multiplication by 3. - 4x4 + 10x3 + 2x2 – 14x ⇐ multiplication by -2x. + 6x3 – 15x2 - 3x + 21 ⇐ multiplication by 4x2. _________________________________ 8x5 – 24x4 + 12x3 + 15x2 – 17x + 21 ⇐ multiplication by (3 - 2x + 4x2). _________________________________ ● Algebraic Expression ● Algebraic Expression ● Addition of Algebraic Expressions ● Subtraction of Algebraic Expressions ● Multiplication of Algebraic Expression ● Division of Algebraic Expressions 8th Grade Math Practice
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