Learn how the values of length are arranged in different columns for the addition of length.

1. Add 15 m 18 cm and 16 m 22 cm

Solution:

Case 1:

Lengths to be added are converted into cm.

15 m 18 cm = 1500 cm + 18 cm = 1518 cm

16 m 22 cm = 1600 cm + 22 cm = 1622 cm

Now, sum

1   1
1518 cm

+ 1622 cm
3140 cm

= 31 m 40 cm

Therefore, 15 m 18 cm + 16 m 22 cm = 31 m 40 cm

Case 2:

m     cm
1       1
15    18

+ 16    22
31    40

(i) First cm are added, 18 cm + 22 cm= 40 cm. This sum is placed under cm column

(ii) Now meters are added, 15 m + 16 m = 31 m. This 31 m is placed under m column.

Hence, sum = 31 m 40 cm.

2. Add 16 m 17 cm and 20 m 23 cm

Solution:

Case 1:

Lengths to be added are converted into cm.

16 m 17 cm = 1600 cm + 17 cm = 1617 cm

20 m 23 cm = 2000 cm + 23 cm = 2023 cm

Now, sum

1
1617 cm

+ 2023 cm
3640 cm

= 36 m 40 cm

Therefore, 16 m 17 cm + 20 m 23 cm = 36 m 40 cm

Case 2:

m   cm
1
16   17
+ 20   23
36   40

(i) First cm are added, 17 cm + 23 cm= 40 cm. This sum is placed under cm column

(ii) Now meters are added, 16 m + 20 m = 36 m. This 36 m is placed under m column.

Hence, sum = 36 m 40 cm.

3. Add 45 m 37 cm and 31 m 92 cm.

Solution:

Case 1:

45 m 37 cm = (45 × 100) cm + 37 cm = (4500 + 37) cm = 4537 cm

31 m 92 cm = (31 × 100) cm + 92 cm = (3100 + 92) cm = 3192 cm

Now, sum

1
4537 cm

+ 3192 cm
7729 cm

= 77 m 29 cm

Therefore, 45 m 37 cm + 31 m 92 cm = 77 m 29 cm

Case 2:

m   cm
1
45   37

+ 31   92
77   29

(i) 37 cm + 92 cm = 129 cm = 1 m 29 cm. 29 is placed under cm column and 1 m is carried over to m column.

(ii) Now 1 m + 45 m + 31 m = 77 m. It is placed under m column.

Hence, sum = 77 m 29 cm.

4. Add 38 m 26 cm, 7 m 5 cm and 45 m 73 cm.

Solution:

The values of length are arranged in columns of m and cm and then added.

m    cm
2 1   1
38   26

7   05

+
45   73

91   04

(i) 26 cm + 05 cm + 73 cm = 104 cm = 1 m 04 cm.

04 is placed under cm column and 1 m is carried over.

(ii) 1 m + 38 m + 7 m + 45 m = 91 m and it is placed under m column.

Hence, the sum = 91 m 04 cm

5. Add 4 km 476 m and 5 km 54 m.

Solution:

Case 1:

Kilometers are changed into meters

4 km 476 m = (4 × 1000) m + 476 m = 4000 m + 476 m = 4476 m

5 km 54 m = (5 × 1000) m + 54 m = 5000 m + 54 m = 5054 m

Now sum

1 1
4476 m

+
5054 m

9530 m

= 9 km 530 m

Therefore, 4 km 476 m + 5 km 54 m = 9 km 530 m

Case 2:

km    m
1 1
4   476

+ 5   054
9   530

(i) 476 m + 054 m = 530 m, which goes under m.

(ii) 4 km + 5 km = 9 km, which goes under km.

Hence, the sum = 9 km 530 m

6. Add 37 km 963 m, 28 km 54 m and 8 km 181 m.

Solution:

Kilometer and meter are arranged in different columns and then added.

km    m
2 1   1
37   963

28   054

+
8   181
74   198

(i) 963 m + 54 m + 181 m = 1198 m = 1 km 198 m.

198 m is placed under column of meters and 1 km is carried over.

(ii) 1 km + 37 km + 28 km + 8 km = 74 km

It is placed under km column.

Hence, the sum = 74 km 198 m

m   dm  cm

26   7     8

+  52   5     6

Solution:

m   dm   cm
1     1
26    7
8

+
52    5    6
79    3    4

(i) 8 cm + 6 cm = 14 cm = 1 dm 4 cm

4 cm is placed under cm column and 1 dm is carried over.

(ii) 7 dm + 5 dm + 1 dm = 13 dm = 1 m 3 dm

3 dm is placed under dm column and 1 m is carried over.

(iii) 1 m + 26 m + 52 m = 79 m

Hence, the sum = 79 m 3 dm 4cm

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