Addition of Capacity

In addition of capacity we will learn how to add the different units of capacity and volume together. While adding we need to follow that the units of capacity i.e., liter and milliliter are converted into milliliters before addition and then follow the simple addition process.

We will learn two different methods to solve addition using the standard unit and smaller unit of capacity. Students can practice both the methods.

(i) Adding units with conversion into milliliters

(ii) Adding units without conversion into milliliters


Worked-out examples on addition of capacity and volume:

1. Add 3 l 600 ml and 6 l 300 ml

Solution:

Method 1 (with conversion into milliliters):

We know, 1 liter = 1000 milliliters

Now liter (l) and milliliters (ml) are converted into ml before doing addition and then we need to follow the simple addition process.

3 l 600 ml = (3 × 1000) ml + 600 ml = 3000 ml + 600 ml = 3600 milliliters

6 l 300 ml = (6 × 1000) ml + 300 ml = 6000 ml + 300 ml = 6300 milliliters

Now sum,

          3600 ml     

      +  6300 ml

          9900 ml

                     = 9 l 900 ml

Therefore, 3 l 600 ml + 6 l 300 ml = 9 l 900 ml


Method 2 (without conversion into milliliters):

Here l and ml are arranged in different columns and then added like ordinary numbers.

(i) l and ml are arranged column-wise

(ii) 600 ml + 300 ml = 900 ml

(iii) 3 l + 6 l = 9 l

            l          ml
            3       600

       +   6       300
            9       900

                         = 9 l 900 ml

Therefore, sum of 3 l 600 ml and 6 l 300 ml = 9 l 900 ml.


2. Add 5 l 725 ml and 8 l 450 ml

Solution:

Method 1 (with conversion into milliliters):

We know, 1 liter = 1000 milliliters

Now liter (l) and milliliters (ml) are converted into ml before doing addition and then we need to follow the simple addition process.

5 l 725 ml = (5 × 1000) ml + 725 ml = 5000 ml + 725 ml = 5725 milliliters

8 l 450 ml = (8 × 1000) ml + 450 ml = 8000 ml + 450 ml = 8450 milliliters

Now sum, 

               1
            5725
ml     

       +   8450 ml
          14175
ml

                      = 14 l 175 ml

Therefore, 5 l 725 ml + 8 l 450 ml = 14 l 175 ml


Method 2 (without conversion into milliliters):

Here l and ml are arranged in different columns and then added like ordinary numbers.

(i) l and ml are arranged column-wise

(ii) 725 ml + 450 ml = 1 l 175 ml.
175 ml is placed under ml. 1 l is taken in l column.

(iii) 1 l + 5 l + 8 l = 14 l

                 l        ml
                1
             5      725

       + 
   8      450
        
  14      175

                         = 14 l 175 ml

Therefore, sum of 5 l 725 ml and 8 l 450 ml = 14 l 175 ml.


More solved examples on addition of capacity where the method is mentioned in the given question.

3. Add 17 l 387 ml, 7 l 750 ml and 9 l without conversion into milliliters

Solution:

Without conversion into milliliters here l and ml are arranged in different columns and then added like ordinary numbers.

(i) l and ml are arranged column-wise

(ii) 387 ml + 750 ml = 1 l 137 ml.
137 ml is placed under ml. 1 l is taken in l column.

(iii) 1 l + 17 l + 7 l + 9 l = 34 l

                     l        ml
                  2 1       1
                  17      387

                    7      750

              +    9      000
                  34      137

                                = 34 l 137 ml

Therefore, sum of 17 l 387 ml, 7 l 750 ml and 9 l = 34 l 137 ml.


4. Add 13 l 250 ml, 8 l 750 ml and 6 l with conversion into milliliters

Solution:

With conversion into milliliters here we will do the addition process.

We know, 1 liter = 1000 milliliters

Now liter (l) and milliliters (ml) are converted into ml before doing addition and then we need to follow the simple addition process.

13 l 250 ml = (13 × 1000) ml + 250 ml = 13000 ml + 250 ml = 13250 milliliters

8 l 750 ml = (8 × 1000) ml + 750 ml = 8000 ml + 750 ml = 8750 milliliters

6 l = (6 × 1000) ml = 6000 milliliters

Now sum, 

              111
           13250 ml  

            8750 ml

       +   6000 ml
          28000
ml

                       = 28 l 000 ml

                       = 28000 ml

Therefore, 13 l 250 ml + 8 l 750 ml + 6 l = 28000 ml


Word problems on addition of capacity and volume:

5. Finn purchased 3 l 250 ml of milk on Monday, 2 l 750 ml on Wednesday and 3 l 500 ml on Friday. How much milk did Finn purchased during these three days?

Solution:

                                                                                              1    1
Milk purchased on Monday                                   =   3
l  250 ml

Milk purchased on Wednesday                              =   2 l  750 ml

Milk purchased on Friday                                     =   3 l  500 ml
                                                                       
+                 

Therefore, total milk purchased during these 3 days =   9 l  500 ml


The above problems on addition of capacity will help the students to practice the worksheet on adding the different units with conversion or without conversion.

Related Concepts

Standard Unit of Capacity

Conversion of Standard Unit of Capacity

Subtraction of Capacity



3rd Grade Math Worksheets

3rd Grade Math Lessons

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