# Word Problems on L.C.M.

Let us consider some of the word problems on l.c.m. (least common multiple).

1. Find the lowest number which is exactly divisible by 18 and 24.

Solution:

We find the L.C.M. of 18 and 24 to get the required number.

L.C.M. = 2 × 3 × 3 × 4 = 72

Therefore, 72 is the required number.

2. Find the lowest number which is less by 5 to be divided by 16, 24 and 36 exactly.

Solution:

We find the L.C.M. of 16, 24 and 36.

L.C.M. = 2 × 2 × 2 × 3 × 2 × 3 = 144

Now subtract 5 from 144 to get the required number.

144 - 5 = 139

Therefore, 139 is the required number.

3. Find the lowest number which is more by 6 to be divided by 25, 40 and 60 exactly.

We find the L.C.M. of 25, 40 and 60.

L.C.M. = 2 × 2 × 5 × 5 × 2 × 3 = 600

Therefore, the required number is 600 + 6 = 606.

4. A shopkeeper sells candles in packets of 12 and candle stands in packet of 8. What is the least number of candles and candle stands Nita should buy so that there will be one candle for each candle stand.

Solution:

To find a quantity which is the lowest common multiple of different quantities, we find the LCM.

Multiples of 12 are 12, 24, 36, 48, ……

Multiples of 8 are 8, 16, 24, 32, 40, ……

The lowest common multiple is 24. So, the least number of candles and candle stand that Nita should buy is 24.

5. Find the lowest number which leaves 3 as remainder when divided by 8, 12 and 16.

Solution:

We find the L.C.M. of 8, 12 and 16.

L.C.M. = 2 × 2 × 2 × 3 × 2 = 48

If we add 3 to 48 it becomes 51 which leaves 3 as remainder when divided by 8, 12 and 16.

Therefore, the required number is 48 + 3 = 51.

6. A florist wants to arrange 24 boquets of flowers in different rows. Find out in how many ways he can arrange the bouquets with same number in each row.

Solution:

We need to find all the factors of 24.

24 = 1 × 24, 24 = 2 × 12, 24 = 3 × 8, 24 = 4 × 6

The factors of 24 are 1, 2, 3, 4, 6, 8, 12 and 24

He can arrange rows of 1, 2, 3, 4, 6, 8, 12 and 24 boquets.

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