Perimeter and Area of Regular Hexagon

Here we will discuss about the perimeter and area of a Regular hexagon and some example problems.

Perimeter (P) = 6 × side = 6a

Area (A) = 6 × (area of the equilateral ∆OPQ)

             = 6 × \(\frac{√3}{4}\) a\(^{2}\)

             = \(\frac{3√3}{2}\) a\(^{2}\)

If the area of a regular hexagon is 24√3 cm², find its perimeter.

Solution: 

Let the side of a regular hexagon be a.

Then, its area = \(\frac{3√3}{2}\) × (Side)²

                     = \(\frac{3√3}{2}\) × a²

Therefore, 24√3 cm² = \(\frac{3√3}{2}\) × a²

⟹  a² = \(\frac{48√3}{3√3}\) cm²

⟹ a² = 16

⟹ Therefore, a ⟹ 4 cm.

Therefore, perimeter = 6a = 6 × 4 cm = 24 cm.

9th Grade Math

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