# Perimeter and Area of Regular Hexagon

Here we will discuss about the perimeter and area of a Regular hexagon and some example problems.

Perimeter (P) = 6 × side = 6a

Area (A) = 6 × (area of the equilateral ∆OPQ)

= 6 × $$\frac{√3}{4}$$ a$$^{2}$$

= $$\frac{3√3}{2}$$ a$$^{2}$$

If the area of a regular hexagon is 24√3 cm2, find its perimeter.

Solution:

Let the side of a regular hexagon be a.

Then, its area = $$\frac{3√3}{2}$$ × (Side)2

= $$\frac{3√3}{2}$$ × a2

Therefore, 24√3 cm2 = $$\frac{3√3}{2}$$ × a2

⟹  a2 = $$\frac{48√3}{3√3}$$ cm2

⟹ a2 = 16

⟹ Therefore, a ⟹ 4 cm.

Therefore, perimeter = 6a = 6 × 4 cm = 24 cm.

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