The three variates which divide the data of a distribution in four equal parts (quarters) are called quartiles. As such, the median is the second quartile.

Lower quartile and the method of finding it for raw data

If the data are arranged in ascending or descending order
then the variate lying at the middle between the lowest variates and the median
is called the lower quartile (or the first quartile), and it is denoted by Q_{1}.

In order to calculate the lower quartile of law data, follow these steps.

**Step I:** Arrange the data in ascending order. (Do not arrange
in descending order.)

**Step II:** Find the number of variates in the data. Let it be
n. Then find the lower quartile as follows.

If n is not divisible by 4 then the mth variate is the lower quartile, where m is the integer just greater then \(\frac{n}{4}\).

If n is divisible by 4 then the lower quartile is the mean of the \(\frac{n}{4}\)th variate and the variate just greater than it.

Solved Problems on Lower Quartile and the Method of Finding it for Raw Data:

**1.** Runs recored by 11 players of a team are 40, 32, 15, 1, 75,
21, 25, 5, 0, 9, 10.

Find the lower quartile of the data.

**Solution:**

Arrange the variates in ascending order, we have

0, 1, 5, 9, 10, 15, 21, 25, 32, 40, 75.

Here, n = 11.

So, \(\frac{n}{4}\) = \(\frac{11}{4}\) = 2.75.

As n is not divisible by 4, m will be an integer just greater than \(\frac{n}{4}\),
i.e., m = 3.

Therefore, the third variate is the lower quartile. So, the
lower quartile Q_{1 }= 5.

**2.** Find the lower quartile of the first twelve natural numbers.

**Solution:**

Here, the variates in ascending order are

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12.

Therefore, n = 12.

So, \(\frac{n}{4}\) = \(\frac{12}{4}\) = 3, i.e., n is divisible by 4.

Therefore, the mean of the 3^{rd} varikate (here 3) and the 4^{th} variate (here 4) is Q_{1}.

Therefore, Q_{1} = \(\frac{3 + 4}{2}\) = 3.5

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