Here we will prove that if a perpendicular is drawn from the right-angled vertex of right-angled triangle to the hypotenuse and if the sides of the right-angled triangle are in continued proportion, the greater segment of the hypotenuse is equal to the smaller side of the triangle.
Solution:
In ∆ XYZ, ∠XYZ = 90°. YP ⊥ XZ.
XY < YZ and YZ < XZ.
Also \(\frac{XY}{YZ}\) = \(\frac{YZ}{XZ}\)
To prove: XY = PZ.
Proof:
Statement |
Reason |
1. ∆ XYZ and ∆ YPZ, (i) ∠XZY = ∠PZY (ii) ∠XYZ = ∠YPZ = 90°. |
1. (i) Common angle. (ii) Given. |
2. ∆ XYZ ∼ ∆ YPZ. |
2. By AA criterion of similarity. |
3. Therefore, \(\frac{YZ}{XZ}\) = \(\frac{PZ}{YZ}\). |
3. Corresponding sides of similar triangles are proportional. |
4. But, \(\frac{XY}{YZ}\) = \(\frac{YZ}{XZ}\). |
4. Given. |
5. Therefore, \(\frac{XY}{YZ}\) = \(\frac{PZ}{YZ}\). |
5. From statements 3 and 4. |
6. Therefore, XY = PZ. (Proved) |
6. From statement 5. |
From Greater segment of the Hypotenuse is Equal to the Smaller Side of the Triangle to HOME PAGE
Didn't find what you were looking for? Or want to know more information about Math Only Math. Use this Google Search to find what you need.
Dec 14, 24 02:12 PM
Dec 14, 24 12:25 PM
Dec 13, 24 08:43 AM
Dec 13, 24 12:31 AM
Dec 12, 24 11:22 PM
New! Comments
Have your say about what you just read! Leave me a comment in the box below. Ask a Question or Answer a Question.