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Converse of Basic Proportionality Theorem

Here we will prove converse of basic proportionality theorem.

The line dividing two sides of a triangle proportionally is parallel to the third side.

Given: In ∆XYZ, P and Q are points on XY and XZ respectively, such that XPPY = XQQZ.

Converse of Basic Proportionality Theorem

To prove: PQ ∥ YZ

Proof:

            Statement

            Reason

1. XPPY = XQQZ.

1. Given

2. PYXP = QZXQ

2. Taking reciprocals of both sides in statement 1.

3. PYXP + 1 = QZXQ + 1

⟹ PY+XPXP = QZ+XQXQ

⟹ XYXP = XZXQ

3. By adding 1 on both sides of statement 2.

4. In ∆XYZ and ∆XPQ,

(i) XYXP = XZXQ

(ii) ∠YXZ = ∠PXQ

4.

(i) From statement 3.

(ii) Common angle

5. Therefore, ∆XYZ ∼ ∆XPQ

5. By SAS criterion of similarity.

6. Therefore, ∠XYZ = ∠XPQ

6. Corresponding angles of similar triangles are equal.

7. YZ ∥ PQ 

7. Corresponding angles are equal.






9th Grade Math

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