# Commutative Property of Multiplication of Complex Numbers

Here we will discuss about the commutative property of multiplication of complex numbers.

Commutative property of multiplication of two complex numbers:

For any two complex number z$$_{1}$$ and z$$_{2}$$, we have z$$_{1}$$z$$_{2}$$ = z$$_{2}$$z$$_{1}$$.

Proof:

Let z$$_{1}$$ = p + iq and z$$_{2}$$ = r + is, where p, q, r and s are real numbers. Them

z$$_{1}$$z$$_{2}$$ = (p + iq)(r + is) = (pr - qs) + i(ps - rq)

and z$$_{2}$$z$$_{1}$$ = (r + is) (p + iq) = (rp - sq) + i(sp - qr)

= (pr - qs) + i(ps - rq), [Using the commutative of multiplication of real numbers]

Therefore, z$$_{1}$$z$$_{2}$$ = z$$_{2}$$z$$_{1}$$

Thus, z$$_{1}$$z$$_{2}$$ = z$$_{2}$$z$$_{1}$$ for all z$$_{1}$$, z$$_{2}$$ ϵ C.

Hence, the multiplication of complex numbers is commutative on C.

Examples on commutative property of multiplication of two complex numbers:

1. Show that multiplication of two complex numbers (2 + 3i) and (3 + 4i) is commutative.

Solution:

Let, z$$_{1}$$ = (2 + 3i) and z$$_{2}$$ = (3 + 4i)

Now, z$$_{1}$$z$$_{2}$$ = (2 + 3i)(3 + 4i)

= (2 3 - 3 4) + (2 4 + 3 3)i

= (6 - 12) + (8 + 9)i

= - 6 + 17i

Again, z$$_{2}$$z$$_{1}$$ = (3 + 4i)(2 + 3i)

= (3 2 - 4 3) + (3 3 + 2 4)i

= (6 - 12) + (9 + 8)i

= -6 + 17i

Therefore, z$$_{1}$$z$$_{2}$$ = z$$_{2}$$z$$_{1}$$

Thus, z$$_{1}$$z$$_{2}$$ = z$$_{2}$$z$$_{1}$$ for all z$$_{1}$$, z2 ϵ C.

Hence, the multiplication of two complex numbers (2 + 3i) and (3 + 4i) is commutative.

2. Show that multiplication of two complex numbers (3 - 2i) and (-5 + 4i) is commutative.

Solution:

Let, z$$_{1}$$ = (3 - 2i) and z$$_{2}$$ = (-5 + 4i)

Now, z$$_{1}$$z$$_{2}$$ = (3 - 2i)(-5 + 4i)

= (3 (-5) - (-2) 4) + ((-2) 4 + (-5) (-2))i

= (-15 - (-8)) + ((-8) + 10)i

= (-15 + 8) + (-8 + 10)i

= - 7 + 2i

Again, z$$_{2}$$z$$_{1}$$ = (-5 + 4i)(3 - 2i)

= ((-5) 3 - 4 (-2)) + (4 3 + (-2) 4)i

= (-15 + 8) + (12 - 8)i

= -7 + 2i

Therefore, z$$_{1}$$z$$_{2}$$ = z$$_{2}$$z$$_{1}$$

Thus, z$$_{1}$$z$$_{2}$$ = z$$_{2}$$z$$_{1}$$ for all z$$_{1}$$, z$$_{2}$$ ϵ C.

Hence, the multiplication of two complex numbers (3 - 2i) and (-5 + 4i) is commutative.

Didn't find what you were looking for? Or want to know more information about Math Only Math. Use this Google Search to find what you need.

## Recent Articles

1. ### Worksheet on Word Problems on Fractions | Fraction Word Problems | Ans

Jul 16, 24 02:20 AM

In worksheet on word problems on fractions we will solve different types of word problems on multiplication of fractions, word problems on division of fractions etc... 1. How many one-fifths

2. ### Word Problems on Fraction | Math Fraction Word Problems |Fraction Math

Jul 16, 24 01:36 AM

In word problems on fraction we will solve different types of problems on multiplication of fractional numbers and division of fractional numbers.

3. ### Worksheet on Add and Subtract Fractions | Word Problems | Fractions

Jul 16, 24 12:17 AM

Recall the topic carefully and practice the questions given in the math worksheet on add and subtract fractions. The question mainly covers addition with the help of a fraction number line, subtractio…

4. ### Comparison of Like Fractions | Comparing Fractions | Like Fractions

Jul 15, 24 03:22 PM

Any two like fractions can be compared by comparing their numerators. The fraction with larger numerator is greater than the fraction with smaller numerator, for example $$\frac{7}{13}$$ > \(\frac{2…