We will discuss here about the usual mathematical operation - addition of two complex numbers.
How do you add Complex Numbers?
Let z\(_{1}\) = p + iq and z\(_{2}\) = r + is be any two complex numbers, then their sum z\(_{1}\) + z\(_{2}\) is defined as
z\(_{1}\) + z\(_{2}\) = (p + r) + i(q + s).
For example, let z\(_{1}\) = 2 + 8i and z\(_{2}\) = -7 + 5i, then
z\(_{1}\) + z\(_{2}\) = (2 + (-7)) + (8 + 5)i = -5 + 13i.
If z\(_{1}\), z\(_{2}\), z\(_{3}\) are any complex numbers, then it is easy to see that
(i) z\(_{1}\) + z\(_{2}\) = z\(_{2}\) + z\(_{1}\) (Commutative law)
(ii) (z\(_{1}\) + z2) + z\(_{3}\) = z\(_{1}\) + (z\(_{2}\) + z\(_{3}\)), (Associative law)
(iii) z + 0 = z = 0 + z, so o acts as the additive identity for the set of complex numbers.
Negative of a complex number:
For a complex number, z = x + iy, the negative is defined as -z = (-x) + i(-y) = -x - iy.
Note that z + (-z) = (x - x) + i(y - y) = 0 + i0 = 0.
Thus, -z acts as the additive inverse of z.
Solved examples on addition of two complex numbers:
1. Find the addition of two complex numbers (2 + 3i) and (-9 - 2i).
Solution:
(2 + 3i) + (-9 - 2i)
= 2 + 3i - 9 - 2i
= 2 - 9 + 3i - 2i
= -7 + i
2. Evaluate: (2√3 + 5i) + (√3 - 7i)
Solution:
2√3 + 5i + √3 - 7i
= 2√3 + √3 + 5i - 7i
= 3√3 - 2i
3. Express the complex number (1 - i) + (-1 + 6i) in the standard form a + ib.
Solution:
(1 - i) + (-1 + 6i)
= 1 - i -1 + 6i
= 1 - 1 - i + 6i
= 0 + 5i, which is the required form.
Note: The final answer of addition of two complex numbers must be in simplest or standard form a + ib.
11 and 12 Grade Math
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