# Adding Numbers in Expanded Form

Learn to arrange for adding numbers in expanded form (in short form and in long form). The numbers are written in column form; the digits are arranged in expanded form and then finally find the sum of the given numbers.

Solved examples on adding numbers in expanded form:

Solution:

Numbers are written in column form        T      O

3       2

+   2       5

5       7

Adding ones:  2 ones + 5 ones = 7 ones

This 7 is written in one’s column.

Adding tens: 3 tens + 2 tens = 5 tens

This 5 is written in tens column.

2. In other way, add the expanded form of the numbers 32 + 25

Solution:

32     =  30 + 2       Expanded form of the numbers

+  25     =  20 + 5

=  50 + 7

=  57

The numbers are written in expanded form as 32 = 30 + 2 and 25 = 20 + 5.

Now digits of one’s place are added, i.e., 2 + 5 = 7.

Again numbers of ten’s place are added, i.e., 30 + 20 = 50

Therefore, total sum = 50 + 7 = 57

3. Add 63 and 35 in long form.

Solution:

Numbers are placed in column

63      Sum of digit of one’s place = 3 ones + 5 ones = 8 ones

+  35     Sum of digit of ten’s place = 6 ten’s + 3 ten’s = 9 ten’s

Therefore, sum =        98      = 9 ten’s + 8 ones

4. Add 38 and 61 in short form.

Solution:

38         Sum of digit of one’s place = 8 + 1 = 9

+   61        Sum of digit of ten’s place = 30 + 60 = 90

Therefore, sum =      99                                              = 90 + 9

5. Add 23, 31 and 44

Solution:

23        Sum of digit of one’s place = 3 + 1 + 4 = 8

+  31       Sum of digit of ten’s place = 2 + 3 + 4 = 9

+  44

Therefore, sum =        98

More solved examples on 3-digits for adding numbers in expanded form.

Solution:

First the digits are arranged in columns

Sum of digit of one’s place = 4 + 3 = 7

Sum of digit of ten’s place = 1 + 6 = 7

Sum of digit of hundred’s place = 3 + 5 = 8

314

+  563

Therefore, sum =     877

7. Add 361 and 527 by arranging the numbers in expanded form.

Solution:

 361 = 3 hundreds + 6 tens + 1 one +  527 = 5 hundreds + 2 tens + 7 one  Sum   = 8 hundreds + 8 tens + 8 one           =888 or,        361 = 300 + 60 + 1         +  527 = 500 + 20 + 7       Sum     = 800 + 80 + 8                  = 888

8. Add 231, 402 and 355

Solution:

231        ones         = 1 + 2 + 5 = 8

+  402        tens         = 3 + 0 + 5 = 8

+  355        hundreds  = 2 + 4 + 3 = 9

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