2-Digit Addition with Carry Over

      Tens         Ones

        1

        5              9

 +     3              7

        9              6 

Therefore, sum of 59 and 37 = 96

(i) Digits at one’s place are added first i.e. 9 + 7 = 16 = 1 ten and 6 ones

(ii) 1 (one) ten is carried over to ten’s side.

(iii) Now digits at tens place are added i.e., 5 + 3 = 8 tens.

To this sum i.e., 8, the carried over 1 ten is also added.

Thus, 8 tens + 1 ten = 9 tens.

(iv) Therefore, sum is 9 tens and 6 ones, i.e., 96.

       Tens        Ones

         1

         6            5

   +    4            7

        11           2

Therefore, sum of 65 and 47 = 112

(i) Digits at one’s place are added first i.e. 5 + 7 = 12 = 1 ten and 2 ones

(ii) 1 (one) ten is carried over to ten’s side.

(iii) Now digits at tens place are added i.e., 6 + 4 = 10 tens.

To this sum i.e., 10, the carried over 1 ten is also added.

Thus, 10 tens + 1 ten = 11 tens.

(iv) Therefore, sum is 11 tens and 2 ones, i.e., 112.

     6 5  =    6 tens   +   5 ones

 +  4 7  =    4 tens   +   7 ones

           =   10 tens   +  12 ones

         = 10 tens + 1 ten + 2 ones

           =   11 tens   +  2 ones

           = 112

5 ones + 7 ones = 12 ones

= 1 ten + 2 ones

6 tens + 4 tens = 10 tens

10 tens + 1 ten (carried over) = 11 tens

The sum = 11 tens + 2 ones

= 112