We will discuss here how to solve the problems based on markups and discounts involving sales tax.
1. Davis bought a car listed at $ 536500 at 8% discount
and then 10% sales tax charged on the discounted price. Find the amount
Davis paid for the car.
Solution:
Price listed on the car = $ 536500, rate of discount = 8%
Therefore, the amount of discount = $ (536500 X 8/100) = $ 42920
Therefore, the selling price of the car = $ (536500  42920) = $ 493580.
The rate of sales tax = 10%
Therefore, the sale tax on the car = $ (493580 X 10/100) = $ 49358
Therefore, the amount paid by Davis = $ (493580 + 49358) = $ 542938.
2. Ron buys a car for $ 38,400 which includes 10% discount and then 6% sales tax on the marked price. Find the marked price of the car.
Solution:
Let the marked price of the car be P. Then, the discount on marked price = 10% of P = 10/100 P = P/10, and sales tax = 6% of P = 6/100 P = 3P/50
Therefore, the price paid = P – P/10 + 3P/50 = 50P – 5P + 3P/50 = 48P/50 = 24P/25
According to the problem we get, 24P/25 = $38400
P = $38400 × 25/24
= $1600 × 25
= $40000
Therefore, the marked price of the car is $40000.
3. Due to short supply in the market, a shopkeeper raises the price of a cycle by 5% above the marked price and charges a sales tax of 12 % on the marked price. A customer has to pay $ 4680 for the cycle. Find the marked price of the cycle.
Solution:
Let the marked price of a cycle be P.
Then, the raised price = P + 5% of P = P + 5P/100 = 21P/20
Sales tax = 12% of P = 12/100 P = 3/25 P
Therefore, the price payable = 21P/20 + 3P/25 = 105P + 12P/100 = 117P/100
According to the problem we get, 117P/100 = $4680
P = $4680 × 100/117
= $4000
Therefore, the marked price of the cycle is $4000.
4. Jack buys a laptop for $ 34821 which includes 10% rebate on the listed price and then 6% sales tax on the remaining price. Find the listed price of the computer.
Solution:
Let the listed price of the laptop be $ x, rebate on the listed price = 10%
Therefore, the amount of rebate = $ (x + 10/100) = $ x/10
Therefore, cost of the laptop after rebate = $ x  $ x/10 = $ 9/10 x
Since sale tax is 6% on the remaining price,
Therefore, the amount of sales tax= $ 9/10x X 6/100 = $ 27/500 x.
Therefore, the net amount to be paid = $ 910x + $ 27/500 x
= $(9/10x + 27/500x)
According to the problem, we get,
9/10x +27/500x = 34821
Or, 477/500x = 34821
Or, x = 36500.
Therefore, the marked price of the laptop = $ 36500.
10th Grade Math
From Markups and Discounts Involving Sales Tax to HOME PAGE
Didn't find what you were looking for? Or want to know more information about Math Only Math. Use this Google Search to find what you need.

New! Comments
Have your say about what you just read! Leave me a comment in the box below. Ask a Question or Answer a Question.