Rule of Separation of Division

Here we will learn the rule of separation of division of algebraic fractions with the help of some problems.

(i) \(\frac{a  +  b}{c} = \frac{a}{c} + \frac{b}{c}\)

(ii) \(\frac{x  -  y}{k} = \frac{x}{k} - \frac{y}{k}\), but \(\frac{k}{x  +  y} \neq \frac{k}{x} + \frac{k}{y}\)

By transposing the above two quantities we get;

(i) \(\frac{a}{c} + \frac{b}{c} = \frac{a  +  b}{c}\)

(ii) \(\frac{x}{k} - \frac{y}{k} = \frac{x  -  y}{k}\)

These means, if two fractions are with same denominator then taking that common denominator as the ‘denominator’ and the sum of the numerators as ’numerator’, we get the sum of the two fractions. Similarly, taking the common denominator as the ‘denominator’ if the difference of the numerators is taken, we get the difference of two fractions.

Now we will learn how to solve the problems by using the rule of separation of division to determine the sum or difference of two algebraic fractions by taking common denominator.


1. Find the sum by taking common denominator:

\(\frac{m}{xy} + \frac{n}{yz}\)

Solution:

We observe the two denominators are xy and yz and their L.C.M. is xyz, so xyz is the least quantity which is divisible by xy and yz. So, keeping the value of \(\frac{m}{xy}\) and \(\frac{n}{yz}\) unchanged xyz should be made their common denominator. So, both the numerator and denominator is to be multiplied by xyz ÷ xy = z in case of \(\frac{m}{xy}\) and xyz ÷ yz = x in case of \(\frac{n}{yz}\).

 Therefore, we can write

\(\frac{m}{xy} + \frac{n}{yz}\)

= \(\frac{m  ∙  z}{xy  ∙  z} + \frac{n  ∙  x}{yz  ∙  x}\) 

= \(\frac{mz}{xyz} + \frac{nx}{xyz}\) 

= \(\frac{mz  +  nx}{xyz}\)


2. Find the difference by taking common denominator:

\(\frac{a}{xy} - \frac{b}{yz}\)

Solution:

There are the two denominators xy and yz and their L.C.M. is xyz. To make both the fractions with the common denominator, both the numerator and denominator of these are to be multiplied by xyz ÷ xy = z in case of \(\frac{a}{xy}\) and by xyz ÷ yz = x in case of \(\frac{b}{yz}\).

 Therefore, we can write

\(\frac{a}{xy} - \frac{b}{yz}\)

= \(\frac{a  ∙  z}{xy  ∙  z} - \frac{b  ∙  x}{yz  ∙   x}\) 

= \(\frac{az}{xyz} - \frac{bx}{xyz}\) 

= \(\frac{az  -  bx}{xyz}\)







8th Grade Math Practice

From Rule of Separation of Division to HOME PAGE




Didn't find what you were looking for? Or want to know more information about Math Only Math. Use this Google Search to find what you need.



New! Comments

Have your say about what you just read! Leave me a comment in the box below. Ask a Question or Answer a Question.




Share this page: What’s this?

Recent Articles

  1. 2nd Grade Data Handling | Collection of Objects |Information Collected

    Dec 15, 24 03:50 PM

    Collection Data
    We have learnt, that a collection of objects can be stored out based on their color, shape, size or any other common thing among them. We can organise all the information in a table to understand how…

    Read More

  2. Patterns in Numbers | Patterns in Maths |Math Patterns|Series Patterns

    Dec 15, 24 10:27 AM

    Complete the Series Patterns
    We see so many patterns around us in our daily life. We know that a pattern is an arrangement of objects, colors, or numbers placed in a certain order. Some patterns neither grow nor reduce but only r…

    Read More

  3. 2nd Grade Geometry Worksheet | Plane and Solid Shapes | Point | Line

    Dec 14, 24 02:12 PM

    Curved Line and Straight Line
    2nd grade geometry worksheet

    Read More

  4. 2nd grade math Worksheets | Free Math Worksheets | By Grade and Topic

    Dec 14, 24 12:25 PM

    2nd Grade Math Worksheet
    2nd grade math worksheets is carefully planned and thoughtfully presented on mathematics for the students.

    Read More

  5. Patterns in Math | Missing Number | Counting Numbers | Worksheets

    Dec 13, 24 12:31 AM

    Finding patterns in math is very important to understand the sequence in the series. We need to find the exact missing number that from the group of numbers. The counting numbers may be counting

    Read More